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laiz [17]
3 years ago
9

In triangle abc, cos A= -0.6. Find A and Tan A

Mathematics
1 answer:
Tresset [83]3 years ago
5 0

Answer:

Part 1) A=126.87^o

Part 2) tan(A)=-\frac{4}{3}

Step-by-step explanation:

we have

cos(A)=-0.6

The cos(A) is negative, that means that the angle A in the triangle ABC is an obtuse angle and the value of the sin(A) is positive

The angle A lie on the II Quadrant

step 1

Find the measure of angle A

cos(A)=-0.6

using a calculator

A=cos^{-1}(-0.6)=126.87^o

step 2

Find the sin(A)

we know that

sin^2(A)+cos^2(A)=1

substitute the value of cos(A)

sin^2(A)+(-0.6)^2=1

sin^2(A)=1-0.36

sin^2(A)=0.64

sin(A)=0.8

step 3

Find tan(A)

we know that

tan(A)=\frac{sin(A)}{cos(A)}

substitute the values

tan(A)=\frac{0.8}{-0.6}

Simplify

tan(A)=-\frac{4}{3}

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At the circus, a clown is shot from a cannon. This situation can be modeled by the function: h = – 16t2 + 45t + 15, where 'h' is
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Answer:

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Step-by-step explanation:

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