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expeople1 [14]
3 years ago
9

A company owns two manufacturing plants with daily production levels of 8x + 17 widgets and 5x - 7 widgets, where x represents a

minimum quantity. How many more items does the first plant produce daily than the second plant?Immersive Reader
Mathematics
1 answer:
pogonyaev3 years ago
3 0

Answer:

3x + 24

Step-by-step explanation:

Given that;

Company owns two manufacting plants with the following daily production levels :

PLANT A:

8x + 17 widgets

PLANT B:

5x - 7 widgets

Where x = minimum quantity

How many more items does the first plant produce daily than the second plant?

Subtract the Plant B's production level from plant A

8x + 17 - (5x - 7)

8x + 17 - 5x + 7

Collecting like terms

8x - 5x + 17 + 7

3x + 24

Hence, the number of items the first plant produce daily than the second plant is :

3x + 24

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ryzh [129]

First find the critical points of <em>f</em> :

f(x,y)=2x^2+3y^2-4x-5=2(x-1)^2+3y^2-7

\dfrac{\partial f}{\partial x}=2(x-1)=0\implies x=1

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so the point (1, 0) is the only critical point, at which we have

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Next check for critical points along the boundary, which can be found by converting to polar coordinates:

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t=2\pi-\cos^{-1}\left(-\dfrac15\right)\implies f(-2,-4\sqrt6)=299

So <em>f</em> has a minimum of -7 and a maximum of 299.

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Answer:

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Step-by-step explanation:

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