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expeople1 [14]
3 years ago
9

A company owns two manufacturing plants with daily production levels of 8x + 17 widgets and 5x - 7 widgets, where x represents a

minimum quantity. How many more items does the first plant produce daily than the second plant?Immersive Reader
Mathematics
1 answer:
pogonyaev3 years ago
3 0

Answer:

3x + 24

Step-by-step explanation:

Given that;

Company owns two manufacting plants with the following daily production levels :

PLANT A:

8x + 17 widgets

PLANT B:

5x - 7 widgets

Where x = minimum quantity

How many more items does the first plant produce daily than the second plant?

Subtract the Plant B's production level from plant A

8x + 17 - (5x - 7)

8x + 17 - 5x + 7

Collecting like terms

8x - 5x + 17 + 7

3x + 24

Hence, the number of items the first plant produce daily than the second plant is :

3x + 24

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RUDIKE [14]

Answer:

16x + 25

Step-by-step explanation:

First, distribute the 8 to both numbers within the parenthesis.

1 + 16x + 24

Then, add similar terms together.

16x + 25

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2 years ago
Perform the indicated operation.(3/a+2) + (4/a-5)
kipiarov [429]

Answer:

\frac{7(a-1)}{(a+2)(a-5)}

Step-by-step explanation:

To solve this operation we need to find the common multiple of both denominators and solve for a.

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