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3 years ago

How many different ways can a president and vice president be selected from a class of 22?

Mathematics

2 answers:

frozen [14]3 years ago

5 0

The answer is D22,2=22*21=462

Schach [20]3 years ago

3 0

Answer: 462

Step-by-step explanation:

Given: The total number of students in a class = 22

Then to select a president and vice president from the class, we need to use Permutations such that the number of different ways can a president and vice president be selected from a class of 22 is given by :-

$^{22}P_2=\frac{22!}{(22-2)!}=\frac{22\times21\times20!}{20!}=21\times22=462$

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