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Veseljchak [2.6K]
3 years ago
9

How many different ways can a president and vice president be selected from a class of 22?

Mathematics
2 answers:
frozen [14]3 years ago
5 0
The answer is D22,2=22*21=462
Schach [20]3 years ago
3 0

Answer: 462

Step-by-step explanation:

Given: The total number of students in a class = 22

Then to select a president and vice president from the class, we need to use Permutations such that the number of different ways can a president and vice president be selected from a class of 22 is given by :-

^{22}P_2=\frac{22!}{(22-2)!}=\frac{22\times21\times20!}{20!}=21\times22=462

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First work out (5/2)³ by cubing both the numerator and denominator to give: 125/8

then work out (3/4)² by squaring both the numerator and denominator to give: 9/16 

then divide 125/8 by 9/16
using the stay-change-flip method of division:
the first term stays the same, the divide becomes multiply and the second fraction is flipped upside down.
so:
125/8 x 16/9 =2000/72
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