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3 years ago

How many different ways can a president and vice president be selected from a class of 22?

Mathematics

2 answers:

frozen [14]3 years ago

5 0

The answer is D22,2=22*21=462

Schach [20]3 years ago

3 0

Answer: 462

Step-by-step explanation:

Given: The total number of students in a class = 22

Then to select a president and vice president from the class, we need to use Permutations such that the number of different ways can a president and vice president be selected from a class of 22 is given by :-

$^{22}P_2=\frac{22!}{(22-2)!}=\frac{22\times21\times20!}{20!}=21\times22=462$

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A truck is said to get 18 miles per gallon on a highway, but this value can fluctuate,

Ratling [72]

Answer: 14 miles ≤ D ≤ 22 miles.

Step-by-step explanation:

The mean distance traveled per gallon, is 18 miles.

But this can fluctuate, at most, by 4 miles.

Because we have here the "at most", we know that we should use the ≤, ≥ symbols.

Then, if the mean is 18mi, the range of possible distances traveled per gallon is:

(18 miles - 4 miles) ≤ D ≤ (18 miles + 4 miles)

Where D is the distance.

14 miles ≤ D ≤ 22 miles.

So the truck can get between 14 miles and 22 miles per gallon on the highway.

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3 years ago

Darcy ordered 18 boxes of red balloons and 12 boxes of blue balloons for a party.She ordered a total of 240 balloons. How many b

olga2289 [7]

Answer: 8 balloons per box
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3 years ago

Find the magnitude of the vector 3i +4j

Nadusha1986 [10]

Answer:

Step-by-step explanation:

magnitude of the vector

=√(3²+4²)

=√25

3 0

3 years ago

The rational expression below is also equal to _____?<br>

Dvinal [7]

The answer is 2 bc I got it right on a quiz

3 0

3 years ago

I really really really need help!!!!

Yakvenalex [24]

For $f$ to be continuous at $x=1$ , you need to have the limit from either side as $x\to1$ to be the same.

$\displaystyle\lim_{x\to1^-}f(x)=\lim_{x\to1^-}(|x-1|+2)=2$
$\displaystyle\lim_{x\to1^+}f(x)=\lim_{x\to1^+}(ax^2+bx)=a+b$

If $a=2$ and $b=3$ , then the limit from the right would be $2+3=5\neq2$ , so the answer to part (1) is no, the function would not be continuous under those conditions.

This basically answers part (2). For the function to be continuous, you need to satisfy the relation $a+b=2$ .

Part (c) is done similarly to part (1). This time, you need to limits from either side as $x\to2$ to match. You have

$\displaystyle\lim_{x\to2^-}f(x)=\lim_{x\to2^-}(ax^2+bx)=4a+2b$
$\displaystyle\lim_{x\to2^+}f(x)=\lim_{x\to2^+}(5x-10)=0$

So, $a$ and $b$ have to satisfy the relation $4a+2b=0$ , or $2a+b=0$ .

Part (4) is done by solving the system of equations above for $a$ and $b$ . I'll leave that to you, as well as part (5) since that's just drawing your findings.

8 0

3 years ago