Answer:
<u>Sum</u><u> </u><u>o</u><u>f</u><u> </u><u>1</u><u> </u><u>a</u><u>n</u><u>d</u><u> </u><u>n</u><u>i</u><u>n</u><u>e</u><u>s</u><u> </u><u>t</u><u>i</u><u>m</u><u>e</u><u>s</u><u> </u><u>a</u><u> </u><u>n</u><u>u</u><u>m</u><u>b</u><u>e</u><u>r</u>
Answer: 3444 boys, 4182 girls
Let there be 14x boys and 17x girls. Then there are 31x total students. Since 31x = 7626, x = 246. Then there are 14(246) = 3444 boys and 17(246) = 4182 girls.
i hope this was helpful! :D
Answer:(0.6,10.6) after 8 seconds.
Step-by-step explanation:
Answer:
0.239 = 23.9% probability that the next game Victoria bowls, her score will be between 123 and 130
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean and standard deviation , the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 130 and a standard deviation of 11.
This means that
What is the probability that the next game Victoria bowls, her score will be between 123 and 130?
This is the p-value of Z when X = 130 subtracted by the p-value of Z when X = 123. So
X = 130
has a p-value of 0.5
X = 123
has a p-value of 0.2611
0.5 - 0.261 = 0.239
0.239 = 23.9% probability that the next game Victoria bowls, her score will be between 123 and 130
We have to determine the relationship between 0.04 and 0.004. The first number, 0.04 is 4 hundredths and the secind number ( 0.004 ) is 4 thousanths. Therefore 0.04 is larger than 0.004. if we divide 0.04 : 0.004 = 40 : 4 = 10. Answer : 0.04 is 10 times greater<span> than 0.004.</span>