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3 years ago

Which of the following equations is quadratic?

Mathematics

2 answers:

Sindrei [870]3 years ago

7 0

Answer:

I think it's 2 because the quadratic equation looks like this ax^2+bx+c=0 and option 2 looks like it.

Step-by-step explanation:

For option 1: x(x^2+1)=0

x^3+1=0 ( This also does not look like the quadratic function, so it couldn't be the answer)

For option 2: (x+3)(x+4)=5

x^2+3x+3x+12=5

x^2+6x+12=5 ( This does look like the quadratic function, so it could be the answer)

For option 3:

5(4x+2)=3

20x+10=3 ( This also does not look like the quadratic function, so it couldn't be the answer)

snow_lady [41]3 years ago

3 0

Answer:

the first one

x(x2 + 1)= 0

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Write the quadratic equation that has roots -1-rt2/3 and -1+rt2/3 if its coefficient with x^2 is equal to 1

weeeeeb [17]

The equation of the quadratic function is f(x) = x²+ 2/3x - 1/9

<h3>How to determine the quadratic equation?</h3>

From the question, the given parameters are:

Roots = (-1 - √2)/3 and (-1 + √2)/3

The quadratic equation is then calculated as

f(x) = The products of (x - roots)

Substitute the known values in the above equation

So, we have the following equation

$f(x) = (x - \frac{-1-\sqrt{2}}{3})(x - \frac{-1+\sqrt{2}}{3})$

This gives

$f(x) = (x + \frac{1+\sqrt{2}}{3})(x + \frac{1-\sqrt{2}}{3})$

Evaluate the products

$f(x) = (x^2 + \frac{1+\sqrt{2}}{3}x + \frac{1-\sqrt{2}}{3}x + (\frac{1-\sqrt{2}}{3})(\frac{1+\sqrt{2}}{3})$

Evaluate the like terms

$f(x) = x^2 + \frac{2}{3}x - \frac{1}{9}$

So, we have

f(x) = x²+ 2/3x - 1/9

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7 0

2 years ago

Help with this please

olga2289 [7]

Answer:

( x + 2 ) and ( x - 11 )

Step-by-step explanation:

x² - 9x - 22 = 0

x² + 2x - 11x - 22 = 0

x ( x + 2 ) - 11 ( x + 2 ) = 0

( x + 2 ) ( x - 11 ) = 0

Factors of x² - 9x - 22 are ( x + 2 ) and ( x - 11 ).

8 0

3 years ago

Read 2 more answers

PLEASE HELP!!

Radda [10]

Answer:

C.) 2 $\sqrt{34}$

Step-by-step explanation:

<em>You must use the pythagorean theorem</em>

the distance on the x axis (or a) is 6

the distance on the y axis (or b) is 10

$6^{2} + 10^{2}$ = 136

$\sqrt{136}$ = 2 $\sqrt{34}$

4 0

3 years ago

Abc is a triangle

alexandr1967 [171]

I’m pretty sure it is 27.89 cm^2

7 0

3 years ago

The teacher passed out math books.The length is 10 inches and the width is 8 inches.What is the perimeter of each book?

miv72 [106K]

Answer: The perimeter of each book is: " 36 in. " .

__________________________________________________

Step-by-step explanation:

__________________________________________________

Note that the given units are all in "inches (in.)" .

Use the formula for the "perimeter of a rectangle" ;

{which happens to work for a "square" as well;

since a "square" is a rectangle.}.

__________________________________________________

This is based on the assumption that the book is shaped like a

"rectangle" (or "square" —which is a rectangle).

__________________________________________________

The formula for the Perimeter of a rectangle is:

P = 2 L + 2 w ;

in which:

P = the perimeter of the rectangle;

for which we shall solve; [in "inches (in.)" ] ;

L = the length of the rectangle = 10 in. (given) ;

w = the width of the rectangle = 8 in. (given) .

___________________________________________________

Now, plug the given values for the "length (L)" and the "width (w)" ;

as follows:

___________________________________________________

P = (2 * 10 in.) + (2 * 8 in.) ;

P = (20 in.) + (16 in.) ;

P = 36 in.

___________________________________________________

Answer: The perimeter of each book is: " 36 in. " .

___________________________________________________

Hope this helps!

Best wishes in your academic pursuits

— and within the "Brainly" community!

___________________________________________________

3 0

3 years ago