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Goryan [66]
3 years ago
5

Help Help Help HELPPP MEEE PLEASEE :<

Mathematics
1 answer:
Galina-37 [17]3 years ago
3 0

Answer:

5600 × 7 = 32, 000 You should multiply

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7 bus loads each carrying 35 students arrived at the game joining 23 students who were already there. Evaluate the expression 23
Irina18 [472]

Answer:

268

Step-by-step explanation:

7*35=245

245+23=268

3 0
3 years ago
How is the graph of y=2x^2+3 different from the graph of y=x^2-9x+20 shown below?
Pepsi [2]

Answer:

○ The graph of y = -2x² + 3 opens downward and is shifted up.

Step-by-step explanation:

According to the Quadratic Equation, <em>y = Ax² + Bx + C</em>, <em>C</em><em> </em>acts<em> </em>like a y-intercept, and in this case, since both graphs shift up [because both are positive values], we do not pay attention to those. Now, we come over to our <em>A</em>, which makes a BIG difference because both graphs open in opposite directions [one negative, one positive]. With this being stated, we have our answer.

If you are ever in need of assistance, do not hesitate to let me know by subscribing to my You-Tube channel [USERNAME: MATHEMATICS WIZARD], and as always, I am joyous to assist anyone at any time.

** Extended information on Parabolas

Opens down → -A

Opens up → A

5 0
3 years ago
Please could you find the answers to the questions in the attachment.
Fudgin [204]
(\frac{x1+x2}{2} , \frac{y1+y2}{2})we need 3 equations
1. midpoint equation which is  (\frac{x1+x2}{2} , \frac{y1+y2}{2}) when you have 2 points

2. distance formula which is D= \sqrt{(x2-x1)^{2}+(y2-y1)^{2}}

3. area of trapezoid formula whhic is (b1+b2) times 1/2 times height


so

x is midpoint of B and C
B=11,10
c=19,6
x1=11
y1=10
x2=19
y2=6
midpoint=(\frac{11+19}{2} , \frac{10+6}{2})
midpoint=(\frac{30}{2} , \frac{16}{2})
midpoint= (15,8)

point x=(15,8)



y is midpoint of A and D
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
midpoint=(\frac{5+21}{2} , \frac{8+0}{2})
midpoint=(\frac{26}{2} , \frac{8}{2})
midpoint=(13,4)

Y=(13,4)



legnths of BC and XY
B=(11,10)
C=(19,6)
x1=11
y1=10
x2=19
y2=6
D= \sqrt{(19-11)^{2}+(6-10)^{2}}
D= \sqrt{(8)^{2}+(-4)^{2}}
D= \sqrt{64+16}
D= \sqrt{80}
D= 4 \sqrt{5}
BC=4 \sqrt{5}





X=15,8
Y=(13,4)
x1=15
y1=8
x2=13
y2=4
D= \sqrt{(13-15)^{2}+(4-8)^{2}}
D= \sqrt{(-2)^{2}+(-4)^{2}}
D= \sqrt{4+16}
D= \sqrt{20}
D= 2 \sqrt{5}
XY=2 \sqrt{5}


the thingummy is a trapezoid
we need to find AD and BC and XY
we already know that BC=4 \sqrt{5} and XY=2 \sqrt{5}

AD distance
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
D= \sqrt{(21-5)^{2}+(0-8)^{2}}
D= \sqrt{(16)^{2}+(-8)^{2}}
D= \sqrt{256+64}
D= \sqrt{320}
D= 4 \sqrt{2}
AD=4 \sqrt{2}


so we have
AD=4 \sqrt{2}
BC=4 \sqrt{5} 
XY=2 \sqrt{5}

AD and BC are base1 and base 2
XY=height
so
(b1+b2) times 1/2 times height
(4 \sqrt{2}+4 \sqrt{5}) times 1/2 times 2 \sqrt{5} =
(4 \sqrt{2}+4 \sqrt{5}) times \sqrt{5} [/tex] =
4 \sqrt{10}+4*5=4 \sqrt{10}+20=80 \sqrt{10}=252.982


























X=(15,8)
Y=(13,4)
BC=4 \sqrt{5}
XY=2 \sqrt{5}
Area=80 \sqrt{10} square unit or 252.982 square units







7 0
3 years ago
A multivitamin tablet contains 0.13g of vitamin C. How much vitamin C does a bottle of 20 tablets contain? Write your answer in
Digiron [165]

Answer:

2600mg

Step-by-step explanation:

0.13*20=2.6g

2.6g=2600mg

7 0
3 years ago
Please answer correctly i need help with these.
vladimir1956 [14]
H = positive (14) because -98 / -7 is 14
U = is (-144) because it has u multiply 6 instead of dividing to remove it. If you do it ot one side you must do it to all other sides.
Q = 18 * 5 is (90)
3 0
3 years ago
Read 2 more answers
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