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ipn [44]
3 years ago
15

A football is left on the field outside during the winter months, the next morning the football was partially deflated. Using wh

at you know about gas laws, explain what happened to the football.
A
Pressure decreases due to less molecular motion of the gas inside the football.

B
Volume decreases due to less molecular motion of the gas inside the football.

C
Volume increases due to more molecular motion of the gas inside the football.

D
Pressure increases due to more molecular motion of the gas inside the football.
Physics
1 answer:
jenyasd209 [6]3 years ago
7 0

Answer:

B  

Volume decreases due to less molecular motion of the gas inside the football.

Explanation:

Assuming that the atmospheric pressure (and therefore, the pressure of the air inside the football) remains constant, this means that we can apply Charle's law, which states that:

"For a fixed amount of gas kept at constant pressure, the volume of the gas is proportional to its absolute temperature"

Mathematically:

\frac{V}{T}=const.

where

V is the volume of the gas

T is its absolute temperature

In the winter month, the air becomes colder, which means that the temperature of the air (and of the gas inside the football) decreases. As the average kinetic energy of the molecules of a gas is proportional to its absolute temperature, this also means that there will be less molecular motion in the gas, and therefore (as stated by Charle's law) the volume of the gas also decreases.

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Three equal point charges, each with charge 1.45 μCμC , are placed at the vertices of an equilateral triangle whose sides are of
LUCKY_DIMON [66]

Answer:

U = 80.91 J

Explanation:

In order to calculate the electric potential energy between the three charges you use the following formula:

U=k\frac{q_1q_2}{r_{1,2}}                  (1)

k: Coulomb's constant = 8.98*10^9Nm^2/C^2

q1: q2 charge

r1,2: distance between charges 1 and 2.

For the three charges you have:

U_T=k\frac{q_1q_2}{r_{1,2}}+k\frac{q_1q_3}{r_{1,3}}+k\frac{q_2q_3}{r_{2,3}}           (2)

You use the fact that q1=q2=q3=q and that the distance between charges are equal. Then, in the equation (2) you have:

q = 1.45μC = 1.45*10^-6C

r = 0.700mm = 0.700*10^-3m

U_T=3k\frac{q^2}{r}=3(8.98*10^9Nm^2/C^2)\frac{(1.45*10^{-6}C)}{0.700*10^{-3}m}\\\\U_T=80.91J

The electric potential energy between the three charges is 80.91 J

7 0
3 years ago
When a car driving up a hill with constant speed: I. its kinetic energy is decreasing. II. its potential energy is constant. III
madam [21]

A car driving up a hill at a constant speed experiences no change in its kinetic energy while it's potential energy increases with increasing height, thus none of the options are correct.

Understanding the concept

Consider a car moving up the hill at a constant speed as shown in the figure below. The following forces act on the car:

  • N is the normal reaction force acting in an upward direction
  • f_s is the static friction force exerted due to friction between the road and the tires of the car
  • f_k is the rolling friction force in the direction opposing that of the  tire
  • mg is the force acting in a downward direction.
  • θ is the angle of inclination.

Here as the car is moving up the hill at a constant speed, the net force exerted on the car is zero. Also, the kinetic energy of the car will not change as its velocity is constant and the potential energy will change with increasing height. Thus, none of the given options are correct.

Learn more about motion on an incline here:

<u>brainly.com/question/13513083</u>

#SPJ4

5 0
2 years ago
A baseball player throws a baseball with a velocity of 13 m/s north. It is caught by a second player seven seconds later. How fa
guajiro [1.7K]

Answer:

A. 91 meters north

Explanation:

Take +y to be north.

Given:

v₀ = 13 m/s

a = 0 m/s²

t = 7 s

Find: Δy

Δy = v₀ t + ½ at²

Δy = (13 m/s) (7 s) + ½ (0 m/s²) (7 s)²

Δy = 91 m

The displacement is 91 m north.

7 0
3 years ago
Anyone who is willing to help me do some 8th grade science questions<br>NO LINKS
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Answer:

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You are working with a team to design a better electron microscope. To precisely control the beam of electrons, your team decide
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Answer and Explanation:

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r = \frac{mV}{qB}

where m = mass of electron, V = velocity of electron, q = charge of the electron and B = magnetic field strength

4 0
3 years ago
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