Question

2. A car is proceeding at a speed of 14.0 m/s when it collidds with a stationary car in front of it.

Answer 1

The force exerted on her is 1700 N

Explanation:

First of all, we start by calculating the acceleration of the car. Since its motion is a uniformly accelerated motion, we can use the following suvat equation:

$v^2-u^2 = 2as$

where

v = 0 is the final velocity of the car (which comes to a stop)

u = 14.0 m/s is the initial velocity

a is the acceleration

s = 3.0 m is the distance covered by the car during the collision

Solving for a,

$a=\frac{v^2-u^2}{2s}=\frac{0-14^2}{2(3)}=-32.7 m/s^2$

And the negative sign means it is a deceleration.

Now we can find the force exerted on the passenger during the collision, using Newton's second law:

$F=ma$

where

F is the force

m = 52.0 kg is the mass of the passenger

$a=32.7 m/s^2$ is the acceleration (we ignore the sign since we are only interested in the magnitude of the force)

Substituting,

$F=(52.0)(32.7)=1700 N$

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