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3 years ago

In an electrically neutral atom of any element, there are equal numbers of

Physics

1 answer:

Alinara [238K]3 years ago

4 0

Answer:

B) Electrons and protons

Explanation:

Each proton has a positive charge, and each electron has a negative charge. If the atom is electrically neutral, there must be the same number of electrons and protons.

A) and C) are wrong. Neutrons have no charge, so they can't counteract that of the protons or the electrons.

D) is wrong. The atomic number is the number of protons, and the mass number is the number of protons plus neutrons. The neutrons can't counteract the charge of the protons,

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An unbalanced force is defined as a force that __________. allows an object to remain at rest cause an object to accelerate in a

fredd [130]

cause an object to accelerate in a direction opposite to the unbalanced force

Explanation:

An unbalanced force is defined as any force that causes an object to accelerate in a direction opposite to the unbalanced force.

The unbalanced force is the net or resultant force describe in newton's second law of motion.

In the first law, it is the external force that causes the motion of a body to change.

Unbalanced forces can cause body to either accelerate in the direction of the force or in an opposite direction of the force.

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3 years ago

Read 2 more answers

Simlarity between longitudanal and transverse waves

babymother [125]

For transverse waves, the waves move in perpendicular direction to the source of vibration. For longitudinal waves, the waves move in parallel direction to the source of vibration . They are similar in the sense that energy is transferred in the form of waves.

8 0

3 years ago

Calculate the wavelength of a photon of electromagnetic radiation with a frequency of 151.7 mhz

AlekseyPX

The wavelength of a photon of electromagnetic radiation with a frequency of 151.7 Mhz is 1.978 meter

According to the question

The frequency of a photon of electromagnetic radiation = 151.7 Mhz

By using the Formula of wavelength and frequency

λ = C/f

Where,

λ (Lambda) = Wavelength in meters

C = Speed of Light (c = 3x10⁸ m/s)

f = Frequency

Now, the wavelength of a photon of electromagnetic radiation with a frequency of 151.7 Mhz is

1 Mhz = 1000000 Hz

151.7 Mhz = 151.7 * 10⁶ Hz

λ = C/f

Substituting the value of C and f

λ = $\frac{3*10^{8} }{151.7 * 10^{6} }$

λ = 1.978 meter

Hence, the wavelength of a photon of electromagnetic radiation with a frequency of 151.7 Mhz is 1.978 meter

To know more about wavelength and frequency here:

brainly.com/question/18651058

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5 0

2 years ago

What must the charge (sign and magnitude) of a particle of mass 1.41 gg be for it to remain stationary when placed in a downward

Yuri [45]

Answer:

$q = 2.067 \times 10^{-5}\ C$

Explanation:

Given,

mass = 1.41 g = 0.00141 Kg

Electric field,E = 670 N/C.

We know,

Force in charge due to Electric field.

F = E q

And also we know

F = m g

Equating both the equation of motion

m g = E q

$q =\dfrac{mg}{E}$

$q =\dfrac{0.00141 \times 9.81}{670}$

$q = 2.067 \times 10^{-5}\ C$

Charge of the particle is equal to $q = 2.067 \times 10^{-5}\ C$

6 0

4 years ago

There is a potential difference of 1.1 V between the ends of a 10 cm long graphite rod that has a cross-sectional area of 0.90 m

Serga [27]

Explanation:

It is given that,

Potential difference between the ends of a rod, V = 1.1 V

Length of the rod, l = 10 cm = 0.1 m

Area of cross section of the rod, $A=0.9\ mm^2=9\times 10^{-7}\ m^2$

The resistivity of graphite, $\rho=7.5\times 10^{-6}\ \Omega-m$

(a) Let R is the resistance of the rod. It is given by :

$R=\rho \dfrac{l}{A}$

$R=7.5\times 10^{-6}\times \dfrac{0.1}{9\times 10^{-7}}$

$R=0.833\ \Omega$

So, the resistance of the rod is 0.833 ohms.

(b) Let I is the current flowing in the wire. It can be calculated using the Ohm's law as :

$I=\dfrac{V}{R}$

$I=\dfrac{1.1\ V}{0.833\ \Omega}$

I = 1.32 A

(c) Let E is the electric field inside the rod. The electric field in terms of potential difference is given by :

$E=\dfrac{V}{l}$

$E=\dfrac{1.1\ V}{0.1\ m}$

E = 11 V/m

Hence, this is the required solution.

8 0

3 years ago