Answer:
x should be 101
Step-by-step explanation:
To solve this problem, we make use of the z statistic. The
formula for z score is:
z = (x – μ) / s
where,
x = is the sample score = 21 or higher
μ = the population mean = 20.8
s = the standard deviation = 4.8
Solving for the z score:
z = (21 – 20.8) / 4.8
z = 0.0417
Next step to do is to find for the p value using the
standard distribution tables at z = 0.04. Since we are looking for the
probability of getting 21 or higher, therefore this is a right tailed test,
hence
p = 0.516
<span>So there is about 51.6% that a student will get a score of
21 or greater.</span>
Answer:
the correct answer is b :)))))!!!
Answer:
The answer is 18p^3r and 63p^3
Step-by-step explanation:
G.C.F of 18p^3 r and 45p^4q is = 9p^3
18p^3r = 2*3*3*p*p*p*r
45p^4q = 3*3*5*p*p*p*q
Thus the G.C.F is 3*3*p*p*p = 9p^3
G.C.F of 63p^3 and 45p^4q is = 9p^3
63p^3 = 3*3*7*p*p*p
45p^4q = 3*3*5*p*p*p*q
Thus the G.C.F is 3*3*p*p*p = 9p^3
Therefore the answer is 18p^3r and 63p^3....
