2x^3-2x^2+3x^2-3x-6x+6
2x^3+x^2-9x+6
Let x represent radius of circle.
We have been given that the height of a cylinder is twice the radius of its base. So height of cylinder would be
.
Now we will use volume of cylinder formula to our given problem.
, where,
r = Radius of base of cylinder,
h = Height of cylinder.
Upon substituting our given values, we will get:


Therefore, our required volume expression would be
.
The maximum mortgage payment allowed for someone with an annual salary of $73.025 would be $2,190.75 per month, so the correct option is A.
<h2><u>How to determine the amount using the standard 28/36 guides?</u></h2>
To determine, using the standard 28/36 guidelines, what is the maximum mortgage payment allowed for someone with an annual salary of $73,025, the following calculation must be made:
- ((73025 x 36) / 100) / 12 = X
- (2,628,900 / 100) / 12 = X
- 26,289 / 12 = X
- 2,190.75 = X
Therefore, the maximum mortgage payment allowed for someone with an annual salary of $73.025 would be $2,190.75 per month.
Learn more about mortgages in brainly.com/question/20589209
Dear Mendozaaj55, 12x + 3y = 6 is a linear function. To find the y-intercept set x = 0 and solve --> 3y = 6 --> y = 2. Therefore, the y-intercept is (0,2). To find the x-intercept, set y = 0 and solve. 12x = 6 ---> x = .5---> the x-intercept is the coordinate (.5, 0). Best.
Part 1:
For this case we must see in the graph the axis of symmetry of the given parabola.
We have then that the axis of symmetry is the vertical line t = 2.
Answer:
The height of the javelin above the ground is symmetric about the line t = 2 seconds:
Part 2:
For this case, we must see the time t for which the javelin reaches a height of 20 feet for the first time.
We then have that when evaluating t = 1, the function is h (1) = 20. To do this, just look at the graph.
Then, we must observe the moment when it returns to be 20 feet above the ground.
For this, observing the graph we see that:
h (3) = 20 feet
Therefore, a height of 20 feet is again reached in 3 seconds.
Answer:
The javelin is 20 feet above the ground for the first time at t = 1 second and again at t = 3 seconds