Question

"Suppose that allele D produces long toes and allele d produces normal toes. A heterozygous male with the Dd genotype mates with a homozygous female with the dd genotype. Long toes is an autosomal dominant trait expressed with 60 % penetrance. Determine the probability that their offspring will have long toes. Report your answer as a percentage without decimal points."

Answer 1

Answer:

30%

Step-by-step explanation:

The crossing of a male with genotype Dd with a female with genotype dd, yields the following possible outcomes:

Dd, dD, dd, dd.

Therefore, there is a 2 in 4, (50%) chance that their offspring will have the dominant allele. Since its penetrance is 60%, the dominant trait will only manifest itself in 60% of heterozygous individuals. Therefore, the probability that their offspring will have long toes is:

$P = 0.50*0.60\\P=30\%$

The probability is 30%.