Let's simplify step-by-step.<span><span><span>12+<span><span>8x</span><span>(<span>4+3</span>)</span></span></span>+2</span>−6</span><span>=<span><span><span><span>12+<span>56x</span></span>+2</span>+</span>−6
</span></span>Combine Like Terms:<span>=<span><span><span>12+<span>56x</span></span>+2</span>+<span>−6</span></span></span><span>=<span><span>(<span>56x</span>)</span>+<span>(<span><span>12+2</span>+<span>−6</span></span>)</span></span></span><span>=<span><span>56x</span>+8
</span></span>Answer:<span>=<span><span>56x</span>+<span>8
Good luck mate :P</span></span></span>
Answer
Are of the pool = w² + 5w (in square feet)
Explanation
Since the pool is rectangular in shape,
Area of the pool can be calculated using the formula for the area of a rectangle
Area of rectangle = length x width
Given,
Width of pool (Assume is same as height) = w
Length of pool= w + 5
Area = w * (w + 5)
= w² + 5w (in square feet)
where w is the width of the pool
you have 10 fish and 3 died (must not have been taking very good care of them ?), but it didnt say that you cleaned them out ...
so you still have 10 fish in the tank
8 more got put in, so 10 + 8 = 18 fish
2 died but you STILL didnt take them out, so you have 18 fish in the tank now.
3x^2 = 7x - 3
3x^2 - 7x = -3
x^2 - 7/3x = -1
x^2 - 7/3x + 49/36 = -1 + 49/36 = 13/36
(x - 7/6)^2 = 13/36
x - 7/6 = + or - sqrt(13)/6
x = 7/6 + or - sqrt(13)/6
x = (7 + or - sqrt(13))/6
