Hello!
First off, please write y2 + y as y^2 + y. The " ^ " symbol denotes exponentiation, whereas y2 is meaningless.
To find the constant term in question, take half of the coefficient of y (that is, take 1/2) and square it. Then we have y2 + y + 1/4.
The constant term in question is 1/4.
<span>6=2+u then u = 6 - 2 = 4
(-16)=(-9)-w then w = 16 - 9 = 7
8=r+4 then r = 8 - 4 = 4
v+(-3)=(-10) then v = -10 + 3 = -7
9=j+7 then j = 9-7 = 2
(-14)=r-6 then r = -14 +6 = -8
(-2)-k=4 then k = -2 -4 = -6
(-10)=n-8 then n = -10 + 8 = -2
(-9)=s+(-4) then s = -9 + 4 = -5
(-4)-s=0 then s = -4</span>
4x - 8 + 6x + 13 = 90
4x + 6x = 90 + 8 - 13
10 x = 85
10x/10 = 85/10
x = 8.5