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3 years ago

I really need help on this geometry question, please, and thank you.

Mathematics

1 answer:

photoshop1234 [79]3 years ago

7 0

Answer:

250

Step-by-step explanation:

you have to use the fact that the big triangle and the small triangle are similar and write the proportions

$\frac{125}{10} =\frac{AB}{10}$ we took half of the side because of ΔABD and ΔBD..

AB= (125*10)/10=125

is AB =125 then AC is duble AC= 2*125=250

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Given that f(x) = x^2? + 9x + 18 and g(x) = x + 3, find (f ÷ g) (x) and express the result in standard form.

lawyer [7]

Answer:

x + 6

Step-by-step explanation:

(f ÷ g)(x)

= $\frac{x^2+9x+18}{x+3}$ factorise the numerator

= $\frac{(x+3)(x+6)}{x+3}$ ← cancel the factor (x + 3) on numerator/ denominator

= x + 6

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3 years ago

The sum of a number and four is less than twelve

Anettt [7]

Answer:

Some answers would be 7 6 5 4 3 2 1. Not all numbers will be less than twelve.

Step-by-step explanation:

First, I added the number to 4 that would equal twelve. Then, I just started using numbers below it. If this is a true or false, this would be false because if you added any number (let's say 12) to 4, you might get more than 12. Although, every number in the negatives would work as well, because they didn't state that the absolute value of the number plus 4 is less than 12. Hope it is right!

6 0

4 years ago

What is the equation of the line that passes through the point<br> (6,7) and has a slope of o?

QveST [7]

Answer:

y= 7

Step-by-step explanation:

Plug in values into y=mx+b

m= slope

b= y intercept

Since slope is 0, y will always be at 7.

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6 0

3 years ago

7.63 repeating as a fraction

Katyanochek1 [597]

Answer:

763/100 is the answer to this

3 0

3 years ago

The vertices of ∆ABC are A(2, 8), B(16, 2), and C(6, 2). what is the perimeter and area in square units

ad-work [718]

Check the picture below.

the triangle has that base and that height, recall that A = 1/2 bh.

now as for the perimeter, you can pretty much count the units off the grid for the segment CB, so let's just find the lengths of AC and AB,

$\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&A&(~ 2 &,& 8~) 
% (c,d)
&C&(~ 6 &,& 2~)
\end{array}~~~ 
% distance value
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
AC=\sqrt{(6-2)^2+(2-8)^2}\implies AC=\sqrt{4^2+(-6)^2}
\\\\\\
AC=\sqrt{16+36}\implies AC=\sqrt{52}\implies AC=\sqrt{4\cdot 13}
\\\\\\
AC=\sqrt{2^2\cdot 13}\implies AC=2\sqrt{13}$

$\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&A&(~ 2 &,& 8~) 
% (c,d)
&B&(~ 16 &,& 2~)
\end{array}\\\\\\
AB=\sqrt{(16-2)^2+(2-8)^2}\implies AB=\sqrt{14^2+(-6)^2}
\\\\\\
AB=\sqrt{196+36}\implies AB=\sqrt{232}\implies AB=\sqrt{4\cdot 58}
\\\\\\
AB=\sqrt{2^2\cdot 58}\implies AB=2\sqrt{58}$

so, add AC + AB + CB, and that's the perimeter of the triangle.

8 0

3 years ago