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marishachu [46]
2 years ago
12

I really need help on this geometry question, please, and thank you.

Mathematics
1 answer:
photoshop1234 [79]2 years ago
7 0

Answer:

250

Step-by-step explanation:

you have to use the fact that the big triangle and the small triangle are similar and write the proportions

\frac{125}{10} =\frac{AB}{10}  we took half of the side because of ΔABD and ΔBD..

AB= (125*10)/10=125

is AB =125 then AC is duble AC= 2*125=250

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Solve 2x2 + 20x = −38. (1 point)
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Answer:

The solutions are x=-5+\sqrt{6}  and x=-5-\sqrt{6}


Step-by-step explanation:

we have

2x^{2} +20x=-38

Divide by 2 both sides

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we know that


The formula to solve a quadratic equation of the form ax^{2} +bx+c=0 is equal to


x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}


in this problem we have


x^{2} +10x+19=0

so


a=1\\b=10\\c=19


substitute

x=\frac{-10(+/-)\sqrt{10^{2}-4(1)(19)}}{2(1)}


x=\frac{-10(+/-)\sqrt{100-76}}{2}


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x=\frac{-10(+/-)2\sqrt{6}}{2}


x1=\frac{-10(+)2\sqrt{6}}{2}=-5+\sqrt{6}


x2=\frac{-10(-)2\sqrt{6}}{2}=-5-\sqrt{6}


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