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guapka [62]
3 years ago
9

Write the Equation of the line in slope intercept form (0, -3), (7.5,0)

Mathematics
1 answer:
makkiz [27]3 years ago
7 0

Answer:

Step-by-step explanation:

First, start off by solving for the slope using this formula:

\frac{y_{2} -y_{1} }{x_{2}-x_{1}  }

Then, plug in the values: \frac{0-(-3)}{7.5-0}

Solve the equation: \frac{3}{7.5}

That's your slope.

Then plug in one of the coordinates given in the problem for x and y and solve this equation:

y=\frac{3}{7.5}x+b

Hope that helped!!! :)

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Lady_Fox [76]

Answer:

simplify

Step-by-step explanation:

7 0
3 years ago
A sample size 25 is picked up at random from a population which is normally
Margarita [4]

Answer:

a) P(X < 99) = 0.2033.

b) P(98 < X < 100) = 0.4525

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 100 and variance of 36.

This means that \mu = 100, \sigma = \sqrt{36} = 6

Sample of 25:

This means that n = 25, s = \frac{6}{\sqrt{25}} = 1.2

(a) P(X<99)

This is the pvalue of Z when X = 99. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{99 - 100}{1.2}

Z = -0.83

Z = -0.83 has a pvalue of 0.2033. So

P(X < 99) = 0.2033.

b) P(98 < X < 100)

This is the pvalue of Z when X = 100 subtracted by the pvalue of Z when X = 98. So

X = 100

Z = \frac{X - \mu}{s}

Z = \frac{100 - 100}{1.2}

Z = 0

Z = 0 has a pvalue of 0.5

X = 98

Z = \frac{X - \mu}{s}

Z = \frac{98 - 100}{1.2}

Z = -1.67

Z = -1.67 has a pvalue of 0.0475

0.5 - 0.0475 = 0.4525

So

P(98 < X < 100) = 0.4525

6 0
3 years ago
Jenna is eating 2 oranges a day to help her diet. She is doing this for all 42 of her oranges. How many days of her diet will Je
ddd [48]

answer:

21 days

Step-by-step explanation:

42/2=21

8 0
3 years ago
Simplify |–9.23 – 1.79| – |–7.34 – 2.57|.
vampirchik [111]

Answer:

11.02-9.91= 1.11

Step-by-step explanation:

|-11.02| - |-9.91|  (First solve in absolute)

11.02 - 9.91        (any values outside absolute becomes positive)

1.11=Ans

6 0
3 years ago
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