2. a) absolute values for the slopes
y = mx + c
3/4, 9,-11, -1 = 3/4, 9,11, 1
the higher the slope, the steeper the graph. 11 is high,
y = -11x - 5
b) 1/4,3,-3/4,-8 = 1/4,3,3/4,8
smaller value is 3/4
the least steep graph will be in,
y = -3/4x + 7
c) 6,2,1, 1/2
1/2 is the smallest value.
y = 1/2x + 6
d) It would be less steep.
e) It would be shifted down.
f) y = -8x - 3
g) y = 1/4x + 9
h) y = 3x - 1
i) y = -5x - 10
3,3 and 12,8 ( this is a guess )
Its just like if u have the #, 8×4-3*2+7
step 1 ; u find the grouping symbols PEMDAS ; 8×4 = 32
Rewrite ; 32-3*2+7
go to the next step ; 3 × 2 = 6
Rewrite ; 32-6+7
next ; 32 - 6 = 26
26 + 7 = 33
so 33 is your answer .
For this case we have the following quadratic equation:
Where:
We look for the solution using the following formula:
Substituting the values:
Thus, we have two roots:
Answer:
Answer:
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