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saw5 [17]
3 years ago
10

A gambler is deciding whether or not to take a bet. She must pay $40 to take the bet, but if she wins, she will profit $225. The

probability that she wins the bet is 1/4 .
a) What is the player's expected value in this situation?
b) If the gambler made this exact bet many times, should she expect to win money or lose money over the long run?
Mathematics
1 answer:
kicyunya [14]3 years ago
6 0

Answer:

The classification of that same given problem is outlined in the following portion on the clarification.

Step-by-step explanation:

⇒  E[x]=\Sigma_{x=0}^{x} \ x \ f(x)

On putting the values, we get

⇒         =0\times \frac{3}{4}+225\times \frac{1}{4}  -40\times 1

⇒         =\frac{225}{4}-40

On taking L.C.M, we get

⇒         =\frac{225-160}{4}

⇒         =\frac{65}{4}

⇒         =16.25

1...

Whether she wins she would receive $225 with even a 1/4 chance, then she will lose and maybe get $0 with such a 3/4 chance although if she takes a gamble anyway though she will either have to compensate $40 wp 1.

2...

She seems to want the capital to benefit or win.

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2. Carl needs 15 hours longer than Jennifer to paint a room. If they work together, they can complete the job in 4 hours. Explai
nasty-shy [4]

Answer:

Jennifer would complete the job on her own in 5 hours.

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\Delta}}{2*a}

x_{2} = \frac{-b - \sqrt{\Delta}}{2*a}

\Delta = b^{2} - 4ac

Rates

The together rate is the sum of their separates rate.

We have that:

Jennifer takes x hours to complete the job on her own, so her rate is 1/x.

Carl needs 15 hours longer than Jennifer, that is, 15 + x hours, so his rate is 1/(15+x).

The together rate is 1/4. So

\frac{1}{4} = \frac{1}{x} + \frac{1}{15+x}

\frac{1}{4} = \frac{15 + x + x}{x(15+x)}

\frac{1}{4} = \frac{15 + 2x}{x(15+x)}

Applying cross multiplication.

x^2 + 15x = 4(15 + 2x)

x^2 + 15x = 60 + 8x

x^2 + 7x - 60 = 0

Quadratic equation with a = 1, b = 7, c = -60. So

\Delta = 7^{2} - 4*1*60 = 289

x_{1} = \frac{-7 + \sqrt{289}}{2} = 5

x_{2} = \frac{-7 - \sqrt{289}}{2} = -12

Since the time to complete the job has to be a positive value.

Jennifer would complete the job on her own in 5 hours.

4 0
3 years ago
In a classroom of 33
amid [387]
Answer: 9 boys
Explanation:
3/11= x/33
11x= 99
x=9
5 0
3 years ago
If the Leaning Tower of Pisa (which is roughly cylindrical) has a height of 55 meters, radius of 8 meters, what is the volume?
valentinak56 [21]

Answer:

Option C. V=3,520\pi\ m^3

Step-by-step explanation:

we know that

The volume of a cylinder is equal to

V=\pi r^{2} h

we have

r=8\ m

h=55/ m

substitute

V=\pi (8)^{2} (55)

V=3,520\pi\ m^3

8 0
3 years ago
Read 2 more answers
A cone has a base with a radius of 9 mm and a height of 13 mm. What is the volume of the cone?
avanturin [10]

\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}

  • Given - <u>a </u><u>cone </u><u>with </u><u>base </u><u>radius </u><u>9</u><u>m</u><u>m</u><u> </u><u>and </u><u>height </u><u>1</u><u>3</u><u> </u><u>mm</u>

  • To calculate - <u>volume </u><u>of </u><u>the </u><u>cone</u>

We know that ,

Volume \: of \: cone =  \frac{1}{3}\pi \: r {}^{2}  h \\

<u>su</u><u>b</u><u>stituting </u><u>the </u><u>values</u><u> </u><u>in </u><u>the </u><u>formula</u><u> </u><u>,</u>

Volume =  \frac{1}{3}  \times  3.14  \times 9 \times 9 \times 13 \\  \\  \implies \: 1.05 \times 81 \times 13 \\  \\ \implies \: 1105.65 \: mm {}^{3}

hope helpful ~

7 0
2 years ago
Express the function graphed on the axes below as a piecewise function.
adoni [48]

Answer:

  f(x) = {x-3 for x ≤ -1; -3x+14 for x > 5}

Step-by-step explanation:

To write the piecewise function, we can consider the pieces one at a time. For each, we need to define the domain, and the functional relation.

__

<h3>Left Piece</h3>

The domain is the horizontal extent. It is shown as -∞ to -1, with -1 included.

The relation has a slope (rise/run) of +1, and would intersect the y-axis at -3 if it were extended.

The first piece can be written ...

  f(x) = x-3 for x ≤ -1

__

<h3>Right Piece</h3>

The domain is shown as 5 to ∞, with 5<em> not included</em>.

The relation is shown as having a slope (rise/run) of (-3)/(1) = -3. If extended, it would intersect the point (5, -1), so we can write the point-slope equation as ...

  y -(-1) = -3(x -5)

  y = -3x +15 -1 = -3x +14

The second piece can be written ...

  f(x) = -3x +14 for x > 5

__

<h3>Whole function</h3>

Putting these pieces together, we have ...

  \boxed{f(x)=\begin{cases}x-3&\text{for }x\le-1\\-3x+14&\text{for }5 < x\end{cases}}

_____

<em>Additional comment</em>

Sometimes it is convenient to write inequalities in number-line order (using < or ≤ symbols). This gives a visual indication of where the variable stands in relation to the limit(s). Perhaps a more conventional way to write the domain for the second piece is, <em>x > 5</em>.

3 0
3 years ago
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