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saw5 [17]
3 years ago
10

A gambler is deciding whether or not to take a bet. She must pay $40 to take the bet, but if she wins, she will profit $225. The

probability that she wins the bet is 1/4 .
a) What is the player's expected value in this situation?
b) If the gambler made this exact bet many times, should she expect to win money or lose money over the long run?
Mathematics
1 answer:
kicyunya [14]3 years ago
6 0

Answer:

The classification of that same given problem is outlined in the following portion on the clarification.

Step-by-step explanation:

⇒  E[x]=\Sigma_{x=0}^{x} \ x \ f(x)

On putting the values, we get

⇒         =0\times \frac{3}{4}+225\times \frac{1}{4}  -40\times 1

⇒         =\frac{225}{4}-40

On taking L.C.M, we get

⇒         =\frac{225-160}{4}

⇒         =\frac{65}{4}

⇒         =16.25

1...

Whether she wins she would receive $225 with even a 1/4 chance, then she will lose and maybe get $0 with such a 3/4 chance although if she takes a gamble anyway though she will either have to compensate $40 wp 1.

2...

She seems to want the capital to benefit or win.

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Student made five tetrahedrons, a three dimensional figure with four triangular faces and labeled the faces 1-4. use an equation
JulsSmile [24]
The probability is 1/1024.

Each tetrahedron has a 1/4 chance of landing on 3, since there are 4 sides and only one of them is marked 3.

Each tetrahedron roll is independent, since no roll is affected by another.

This means we multiply the probabilities:
1/4(1/4)(1/4)(1/4)(1/4) = 1/1024
3 0
3 years ago
Read 2 more answers
Find derivative problem<br> Find B’(6)
dalvyx [7]

Answer:

B^\prime(6) \approx -28.17

Step-by-step explanation:

We have:

\displaystyle B(t)=24.6\sin(\frac{\pi t}{10})(8-t)

And we want to find B’(6).

So, we will need to find B(t) first. To do so, we will take the derivative of both sides with respect to x. Hence:

\displaystyle B^\prime(t)=\frac{d}{dt}[24.6\sin(\frac{\pi t}{10})(8-t)]

We can move the constant outside:

\displaystyle B^\prime(t)=24.6\frac{d}{dt}[\sin(\frac{\pi t}{10})(8-t)]

Now, we will utilize the product rule. The product rule is:

(uv)^\prime=u^\prime v+u v^\prime

We will let:

\displaystyle u=\sin(\frac{\pi t}{10})\text{ and } \\ \\ v=8-t

Then:

\displaystyle u^\prime=\frac{\pi}{10}\cos(\frac{\pi t}{10})\text{ and } \\ \\ v^\prime= -1

(The derivative of u was determined using the chain rule.)

Then it follows that:

\displaystyle \begin{aligned} B^\prime(t)&=24.6\frac{d}{dt}[\sin(\frac{\pi t}{10})(8-t)] \\ \\ &=24.6[(\frac{\pi}{10}\cos(\frac{\pi t}{10}))(8-t) - \sin(\frac{\pi t}{10})] \end{aligned}

Therefore:

\displaystyle B^\prime(6) =24.6[(\frac{\pi}{10}\cos(\frac{\pi (6)}{10}))(8-(6))- \sin(\frac{\pi (6)}{10})]

By simplification:

\displaystyle B^\prime(6)=24.6 [\frac{\pi}{10}\cos(\frac{3\pi}{5})(2)-\sin(\frac{3\pi}{5})] \approx -28.17

So, the slope of the tangent line to the point (6, B(6)) is -28.17.

5 0
3 years ago
Can sum one help me
sleet_krkn [62]

Answer:

help with what exactly

8 0
3 years ago
Please help me with this please and thank you
melamori03 [73]

Answer:

B

Step-by-step explanation:

let X represent the smaller paintings and Y represent the larger paintings

since she bought 8 paintings

X+Y=8

She bought all the eight paintings for $230 and X is worth 25 while Y is worth 40

25×X+40×Y=230

25X+40Y=230

7 0
2 years ago
PLEASE HELP mE: Expand the expression 0.9(7x - 1) + 9?
Alex_Xolod [135]

Answer:

6.3x+8.1 simplify

Step-by-step explanation:

8 0
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