Answer:
The quotient of this division is (2x + 3y) with remainder 0
Step-by-step explanation:
The given division is as :
( 8x² + 8xy +6x - 6y² + 9y ) ÷ ( 4x - 2y + 3)
<u>Multiply the divisor by 2x</u>
Or, (4x - 2y + 3) × (2x ) = 8x²- 4xy + 6x
so, ( 8x² + 8xy +6x - 6y² + 9y ) - (8x² - 4xy + 6x) = 12xy - 6y² +9y
<u>Again multiply the divisor by 3y </u>
Again , (4x - 2y + 3) × (3y ) = 12xy -6y² +9y
Or, (12xy - 6y² +9y) - (12xy - 6y² +9y) = 0
So from division method we get the quotient as (2x + 3y ) and remainder is 0 Answer
