But it could also be the case that 4 is the hypotenuse and 3 is one of the legs. In this case, the missing side is the other leg, so we calculate it using

$\sqrt{4^2-3^2}=\sqrt{16-9}=\sqrt{7}$

So, a right triangle with legs $\sqrt{7}$ and 3 has an hypotenuse of 4.

8 0

3 years ago

Pls need help 100 points and crown if right!!!

nekit [7.7K]

Answer:

$\sf 2\dfrac{1}{4}\ cups \ of \ sugar$

Explanation:

Let the full batch be x

Here given:

3/4 cup of sugar required to make 1/3 batch of cookies

Build equation:

$\sf \rightarrow \dfrac{1}{3}x = \dfrac{3}{4} \ cup \ of \ sugar$

Solve:

$\sf \rightarrow x = \dfrac{3(3)}{1(4)}$

$\sf \rightarrow x = \dfrac{9}{4}$

$\rightarrow \sf x = 2\dfrac{1}{4}$

5 0

1 year ago

Read 2 more answers

Urgenttttt please I need it fast

dolphi86 [110]

Answer:

Below in bold.

Step-by-step explanation:

c) 3 x (9^2)^3/4 x ((81^3)^5/6

= 3 x 81^3/4 x 81^15/6

= 3 x 81^(3/4 + 15/6)

= 3 x 81^13/4

= 3 x 3^13

= 3^14

= 4,782,969.

f) (5x^-1y^2)^-2 / (25 x^2 y - 1)^2

= 5^-2 x^2y^-4 / 625 x^4y^-2

= 5^-2 x^-2 y^-2 / 5^4

= 5^-6 x^-2y^-2

= 0.000064x^-2y^-2.

5 0

3 years ago

ILL GIVE BRAINLEST ​

ILL GIVE BRAINLEST