The answer is C that’s all I can give to you
What you need to do is to find a multiple of 20 and 16 in other words a number that can multiply into 20 and 16. You have 2 and you have 4. So now this is how it looks like.
Either:
4(5+4) Or
2(10+8)
<h3>Answer: Choice D
</h3>
=======================================================
Explanation:
Let's go through the answer choices one by one to see which are true, and which are false.
- Choice A) This is true because as we approach x = 2 from the left hand side, the y values get closer to y = 1 from the top
- Choice B) This is true. As we get closer to x = 4 on the left side, the blue curve is heading downward forever toward negative infinity. So this is what y is approaching when x approaches 4 from the left side.
- Choice C) This is true also. The function is continuous at x = -3 due to no gaps or holes at this location, so that means its limit here is equal to the function value.
- Choice D) This is false. The limit does exist and we find it by approaching x = -4 from either side, and we'll find that the y values are approaching y = -2. In contrast, the limit at x = 2 does not exist because we approach two different y values when we approach x = 2 from the left and right sides (approach x = 2 from the left and you get closer to y = 1; approach x = 2 from the right and you get closer to y = -2). So again, the limit does exist at x = -4; however, the function is not continuous here because its limiting value differs from its function value.
- Choice E) This is true because the function curve approaches the same y value from either side of x = 6. Therefore, the limit at x = 6 exists.
Answer:
x
+
y
=
2
, y
=
x
2
−
4
x
+
4
Replace all occurrences of
y
with x
2
−
4
x
+
4
in each equation.
x
2
−
3
x
+
4
=
2
y
=
x
2
−
4
x
+
4
Solve for
x
in the first equation.
x
=
2
,
1
y
=
x
2
−
4
x+
4
Replace all occurrences of
x with 2
in each equation.
y=0
x
=
2
Replace all occurrences of x
with 1
in each equation.
y
=
1
x
=
1
The solution to the system is the complete set of ordered pairs that are valid solutions.
(
2
,
0
)
(
1
,
1
)
The result can be shown in multiple forms.
Point Form:
(
2
,
0
)
,
(
1
,
1
)
Equation Form:
x=2
,
y
=
0
x
=
1
,
y
=
1
Step-by-step explanation:
