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laila [671]
3 years ago
10

Austin's truck has a mass of 2000 kg when traveling at 22.0 m/s, it brakes to a stop in 4.0 s. show that the magnitude of the br

aking force acting on the truck is 11,000 n

Mathematics
2 answers:
olga2289 [7]3 years ago
5 0
Since F=m•a, you want to show that a = -5.5

Andrei [34K]3 years ago
5 0

Since the truck was in motion before the brakes were applied, it will decelerate within the 4s before coming to a stop. Hence the acceleration is -a\:ms^{-2}.

When the truck comes to a stop, It will have a final velocity of v=0\:ms^{-1}.

Also the initial velocity is 22.0 m/s. This means, u=22.0\:ms^{-1} and time,  t=4s.


We can use the relation,

v=u+at

to determine the acceleration of the truck.

Let us now plug in all the values to obtain,

0=22.0+(-a)(4)

\Rightarrow -22.0=-4a

\Rightarrow \frac{-22.0}{-4}=a


\Rightarrow a=5.5 ms^{-2}

Using the relation,

F=ma

the magnitude of the braking force is

F=2000 \times 5.5 N=11000N

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