3 years ago

Please help. I’ll mark you as brainliest if correct!

Mathematics

1 answer:

OLEGan [10]3 years ago

5 0

Answer:

x +0y+0z = 400

-x +y+0z = 150

-8x +0y +z = 250

Step-by-step explanation:

The last column is the solution

The rest of the columns are the coefficients of the variables

x +0y+0z = 400

-x +y+0z = 150

-8x +0y +z = 250

You might be interested in

Hi . Anyone who sees this I need help if you know of I have a question whats the answer and I way i can show my work the equatio

Shkiper50 [21]

Answer: yes use m a t h w a y !!

6 0

3 years ago

Divide (18x^3 + 12x – 3x) ÷ 6x^2

andre [41]

First let's simplify it

$\frac{18x^3 + 9x}{6x^2}$

Now let's factor it
$\frac{9x(2x^2 + 1)}{6x^2}$

Lastly, let's simplify
$\frac{3(2x^2 + 1)}{2x}$

4 0

3 years ago

Alison is buying binders for school. Small binders cost $3 each, and large binders cost $5 each. If Alison needs to buy at least

Mariulka [41]

Answer:

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Can someone please simplify 81^5 = 3^x

artcher [175]

If you are trying to find the answer for x it would 20

5 0

3 years ago

Ierofanga [76]

Answer:

Step-by-step explanation:

Sum the product of the components in the first row of A with the corresponding components of the first column in B

Repeat this with the components in the second row of A with the corresponding components of the second column in B, that is

= $\left[\begin{array}{ccc}2&1\\3&4\\\end{array}\right]$ $\left[\begin{array}{ccc}3&1\\5&2\\\end{array}\right]$

= $\left[\begin{array}{ccc}2(3)+1(5)&2(1)+1(2)\\3(3)+4(5)&3(1)+4(2)\\\end{array}\right]$

= $\left[\begin{array}{ccc}6+5&2+2\\9+20&3+8\\\end{array}\right]$

= $\left[\begin{array}{ccc}11&4\\29&11\\\end{array}\right]$ → A

6 0

3 years ago