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Sauron [17]
3 years ago
8

Please help. I’ll mark you as brainliest if correct!

Mathematics
1 answer:
OLEGan [10]3 years ago
5 0

Answer:

x +0y+0z = 400

-x +y+0z = 150

-8x +0y +z = 250

Step-by-step explanation:

The last column is the solution

The rest of the columns are the coefficients of the variables

x +0y+0z = 400

-x +y+0z = 150

-8x +0y +z = 250

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Half a number plus 2.5 times that number equals 18. What is the number?
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Tua madre Puttana quella troia inculata schifosa
6 0
3 years ago
In a G.P the difference between the 1st and 5th term is 150, and the difference between the
liubo4ka [24]

Answer:

Either \displaystyle \frac{-1522}{\sqrt{41}} (approximately -238) or \displaystyle \frac{1522}{\sqrt{41}} (approximately 238.)

Step-by-step explanation:

Let a denote the first term of this geometric series, and let r denote the common ratio of this geometric series.

The first five terms of this series would be:

  • a,
  • a\cdot r,
  • a \cdot r^2,
  • a \cdot r^3,
  • a \cdot r^4.

First equation:

a\, r^4 - a = 150.

Second equation:

a\, r^3 - a\, r = 48.

Rewrite and simplify the first equation.

\begin{aligned}& a\, r^4 - a \\ &= a\, \left(r^4 - 1\right)\\ &= a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right) \end{aligned}.

Therefore, the first equation becomes:

a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right) = 150..

Similarly, rewrite and simplify the second equation:

\begin{aligned}&a\, r^3 - a\, r\\ &= a\, \left( r^3 - r\right) \\ &= a\, r\, \left(r^2 - 1\right) \end{aligned}.

Therefore, the second equation becomes:

a\, r\, \left(r^2 - 1\right) = 48.

Take the quotient between these two equations:

\begin{aligned}\frac{a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right)}{a\cdot r\, \left(r^2 - 1\right)} = \frac{150}{48}\end{aligned}.

Simplify and solve for r:

\displaystyle \frac{r^2+ 1}{r} = \frac{25}{8}.

8\, r^2 - 25\, r + 8 = 0.

Either \displaystyle r = \frac{25 - 3\, \sqrt{41}}{16} or \displaystyle r = \frac{25 + 3\, \sqrt{41}}{16}.

Assume that \displaystyle r = \frac{25 - 3\, \sqrt{41}}{16}. Substitute back to either of the two original equations to show that \displaystyle a = -\frac{497\, \sqrt{41}}{41} - 75.

Calculate the sum of the first five terms:

\begin{aligned} &a + a\cdot r + a\cdot r^2 + a\cdot r^3 + a \cdot r^4\\ &= -\frac{1522\sqrt{41}}{41} \approx -238\end{aligned}.

Similarly, assume that \displaystyle r = \frac{25 + 3\, \sqrt{41}}{16}. Substitute back to either of the two original equations to show that \displaystyle a = \frac{497\, \sqrt{41}}{41} - 75.

Calculate the sum of the first five terms:

\begin{aligned} &a + a\cdot r + a\cdot r^2 + a\cdot r^3 + a \cdot r^4\\ &= \frac{1522\sqrt{41}}{41} \approx 238\end{aligned}.

4 0
3 years ago
Isabella bought 4.5 bags of candy for her party baskets. Each bag has 146 pieces of candy. If she has 9 party baskets, how many
Nadusha1986 [10]
73 because 4.5x146= 657 and 657/9= 73
7 0
2 years ago
Read 2 more answers
A+B=44 A+B=44 A:B A:B is equivalent to 4:7. A= B=
ipn [44]
I think is going to be
A=1
B=43 
I WISH IF YOU LOOKING FOR
6 0
4 years ago
How do you solve f (x)=-3 (x+2)+2
Allushta [10]

Answer:

−1/3y+−4/3

Step-by-step explanation:

We need to solve for x.

How? Easy! :D

Step one: Flip the equation. (In class we call it the 'flip-flop'.) When you do this, you should have your equation look like this:

−3x−4=y

Step two: Add 4 to both sides of the equation. When you do this step, your problem should look like this:

−3x−4+4=y+4

−3x=y+4

Step three: Divide both sides by -3.

-3x/-3 = y+4/-3.

Step four: Wrap-up. What the answer is.

x = -1/3y + -4/3

Final step: OUR ANSWER!

x = -1/3 + -4/3

Hope this helped! :D

5 0
3 years ago
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