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Norma-Jean [14]
4 years ago
6

You're in an airplane that flies horizontally with speed 1100 km/h (300 m/s ) when an engine falls off. Neglecting air resistanc

e, assume it takes 26 s for the engine to hit the ground.Find the height of airplane.
Physics
1 answer:
Tcecarenko [31]4 years ago
5 0

Answer:

The height of the airplane is 3312.4 meters.

Explanation:

Given that,

Speed of the airplane, v = 1100 km/h = 300 m/s

It takes 26 s for the engine to hit the ground. We need to find the height of the airplane. Using second equation of motion to find it as :

h=ut+\dfrac{1}{2}at^2

Here, u = 0 and a = g

h=\dfrac{1}{2}gt^2\\\\h=\dfrac{1}{2}\times 9.8\times (26)^2\\\\h=3312.4\ m

The height of the airplane is 3312.4 meters.

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Problem 7.17 A horizontal spring with stiffness 0.8 N/m has a relaxed length of 12 cm (0.12 m). A mass of 23 grams (0.023 kg) is
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The speed of the mass v = 0.884 m/s.

<u>Explanation</u>:

Let

K1 represents the kinetic energy of the mass when it is released,

U1 represents the potential energy of the spring when the mass is released,

K2 represents the kinetic energy of the mass when the spring returns to relaxed length,

U2 represents the potential energy of the spring when the spring returns to relaxed length

The spring is stretched by 0.27 - 0.12 = 0.15 m

                                K1 = 0

                                 U1 = (1/2) \times 0.8 \times (0.15)^2

                                     = 0.009 J

                                U2 = 0

By conservation of energy,

                        K2 + U2 = K1 + U1

                           K2 + 0 = 0 + 0.009 J

                                 K2 = 0.009 J

Let v = speed of the mass

                                K2 = 1/2 \times m \times v^2

m = 23 g = 0.023 kg

                           0.009 = 1/2 \times 0.023 \times v^2

                           0.009 = 0.0115 \times v^2

                                   v = √(0.009 / 0.0115)

                                  v = 0.884 m/s.

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