Answer:
The angle between the red and blue light is 1.7°.
Explanation:
Given that,
Wavelength of red = 656 nm
Wavelength of blue = 486 nm
Angle = 37°
Suppose we need to find the angle between the red and blue light as it leaves the prism
![n_{r}=1.572](https://tex.z-dn.net/?f=n_%7Br%7D%3D1.572)
![n_{b}=1.587](https://tex.z-dn.net/?f=n_%7Bb%7D%3D1.587)
We need to calculate the angle for red wavelength
Using Snell's law,
![n_{r}\sin\theta_{i}=n_{a}\sin\theta_{r}](https://tex.z-dn.net/?f=n_%7Br%7D%5Csin%5Ctheta_%7Bi%7D%3Dn_%7Ba%7D%5Csin%5Ctheta_%7Br%7D)
Put the value into the formula
![1.572\sin37=1\times\sin\theta_{r}](https://tex.z-dn.net/?f=1.572%5Csin37%3D1%5Ctimes%5Csin%5Ctheta_%7Br%7D)
![\theta_{r}=\sin^{-1}(\dfrac{1.572\sin37}{1})](https://tex.z-dn.net/?f=%5Ctheta_%7Br%7D%3D%5Csin%5E%7B-1%7D%28%5Cdfrac%7B1.572%5Csin37%7D%7B1%7D%29)
![\theta_{r}=71.0^{\circ}](https://tex.z-dn.net/?f=%5Ctheta_%7Br%7D%3D71.0%5E%7B%5Ccirc%7D)
We need to calculate the angle for blue wavelength
Using Snell's law,
![n_{b}\sin\theta_{i}=n_{a}\sin\theta_{b}](https://tex.z-dn.net/?f=n_%7Bb%7D%5Csin%5Ctheta_%7Bi%7D%3Dn_%7Ba%7D%5Csin%5Ctheta_%7Bb%7D)
Put the value into the formula
![1.587\sin37=1\times\sin\theta_{b}](https://tex.z-dn.net/?f=1.587%5Csin37%3D1%5Ctimes%5Csin%5Ctheta_%7Bb%7D)
![\theta_{b}=\sin^{-1}(\dfrac{1.587\sin37}{1})](https://tex.z-dn.net/?f=%5Ctheta_%7Bb%7D%3D%5Csin%5E%7B-1%7D%28%5Cdfrac%7B1.587%5Csin37%7D%7B1%7D%29)
![\theta_{b}=72.7^{\circ}](https://tex.z-dn.net/?f=%5Ctheta_%7Bb%7D%3D72.7%5E%7B%5Ccirc%7D)
We need to calculate the angle between the red and blue light
Using formula of angle
![\Delta \theta=\theta_{b}-\theta_{r}](https://tex.z-dn.net/?f=%5CDelta%20%5Ctheta%3D%5Ctheta_%7Bb%7D-%5Ctheta_%7Br%7D)
Put the value into the formula
![\Delta \theta=72.7-71.0](https://tex.z-dn.net/?f=%5CDelta%20%5Ctheta%3D72.7-71.0)
![\Delta \theta=1.7^{\circ}](https://tex.z-dn.net/?f=%5CDelta%20%5Ctheta%3D1.7%5E%7B%5Ccirc%7D)
Hence, The angle between the red and blue light is 1.7°.
Answer:
Yes, it is reckless. This is because it is the responsibility of the pilot to make sure that the direction of the propeller blast is away from people or other aircraft and in a safe direction.
Explanation:
Yes, it is reckless to let the propeller blast face people and other aircraft. This is because it is the responsibility of the pilot to make sure that the direction of the propeller blast is away from people or other aircraft and in a safe direction. People and other aircraft can be injured by the debris and the rocks that are scattered by the engine of the aircraft.
Answer:
Explanation:
Let T be the tension .
Applying newton's second law on the downward movement of the bucket
mg - T = ma
On the drum , a torque of TR will be acting which will create an angular acceleration of α in it . If I be the moment of inertia of the drum
TR = Iα
TR = Ia/ R
T = Ia/ R²
Replacing this value of T in the other equation
mg - T = ma
mg - Ia/ R² = ma
mg = Ia/ R² +ma
a ( I/ R² +m)= mg
a = mg / ( I/ R² +m)
mg - T = ma
mg - ma = T
mg - m x mg / ( I/ R² +m) = T
mg - m²g / ( I/ R² +m ) = T
mg - mg / ( 1 + I / m R² ) = T
b ) T = Ia/ R²
I = TR² / a
c ) Moment of inertia of hollow cylinder
I = 1/2 M ( R² - R² / 4 )
= 3/4 x 1/2 MR²
= 3/8 MR²
I / R² = 3/8 M
a = mg / ( I/ R² +m)
a = mg / ( 3/8 M + m )
T = Ia/ R²
= 3/8 MR² x mg / ( 3/8 M + m ) x 1 /R²
= ![\frac{3mMg}{(3M +8m)}](https://tex.z-dn.net/?f=%5Cfrac%7B3mMg%7D%7B%283M%20%2B8m%29%7D)
P=IV, where P is power, I is resistance, and V is voltage. Plug in and solve:
P=400(20)
P=8000W
Hope this helps!!