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Fantom [35]
3 years ago
6

Width, height, thickness and thermal conductivity of a single pane window and the air space of a double pane window. Representat

ive winter surface temperatures of single pane and air space. FIND: Heat loss through single and double pane windows.

Physics
1 answer:
KonstantinChe [14]3 years ago
5 0

Complete Question

The schematics is shown on the first uploaded image

Answer:

For single pane is  Q  =1.96 *10^{4}} \  W  

For  double pane is  Q_2  = 120 \  W

Explanation:

Generally the heat loss through  a single pane is mathematically represented by  Fourier’s law as

      Q  =  k_g *  H^2  *  \frac{ T_1 - T_2 }{L}

=>    Q  =  1.4  *  2^2 *  \frac{ 15 -(-20)  }{ 5 *  \frac{1 \ m}{1000 \ mm}}

=>    Q  =1.96 *10^{4}} \  W        

Generally the heat loss through  a double pane is mathematically represented by  Fourier’s law as

      Q_2  =  k_a *  H^2  *  \frac{ T_1 - T_2 }{L}

=>    Q_2  =  0.024  *  2^2 *  \frac{ 10 -(-15)  }{ 10 *  \frac{1 \ m}{1000 \ mm}}

=>    Q_2  = 120 \  W  

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g: gravitational acceleration = 9.8 ms^2

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y1: -2m

(the height is measure from the water level, because of that, the heights are negative)

You solve the equation (1) for P1:

P_1=P_2-\rho g(y_2-y_1)         (2)

Next, you replace the values of all variables in equation (2):

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3 years ago
Read 2 more answers
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