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anzhelika [568]
3 years ago
6

Which graphs represents this system of inequalities?

Mathematics
1 answer:
MAVERICK [17]3 years ago
5 0

Answer:

  • by using desmos graphing.....
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U^3-512=()(u^2+8u+64)
crimeas [40]

Answer:

u=8

Step-by-step explanation:

8 0
3 years ago
The slope of a line is -4 and it’s y-intercept is (0,4) what is the equation of the line that is perpendicular to the first line
Rasek [7]

Original line equation: y=-4x+4

Perpendicular lines have opposite reciprocals, so the slope of the perpendicular line would be 1/4x.

Perpendicular line equation: y=1/4x+b

Plug in the coordinates that the line passes through to solve for b. Plug -8 in for x and 2 in for y.

2=1/4(-8)+b

Multiply.

2=-2+b

Add 2 to both sides.

4=b

Equation of the perpendicular line: y=1/4x+4

Hope this helps! :)

4 0
3 years ago
How do I draw a model for 63 divided 6
Marianna [84]
This is a model of 63÷6. :)

4 0
3 years ago
• What can you say about the values of 180 and 2x2x3x3x5?
kiruha [24]

Answer:

2×2×3×3×5 are the prime factors of 180

Step-by-step explanation:

If you draw a factor tree, you would find that 2x2x3x3x5 are the prime factors of 180

hope this helps :)

8 0
3 years ago
Find the equation of a straight line passing throught the point listed and having the given gradient. Express your answer in the
Igoryamba
First let's try to find the equation in this form : <span>y = mx + c 

The gradient is given 3 . In a line's equation, x's coefficient represents the line's gradient.

So equation of a line with the gradient of 3, would look like this ;

</span>y= 3x + c
<span>
Now a point that the line passes through is given, (1, 2) 

This point's x-coordinate is 1 and y-coordinate is 2.

So we'll plug its x-coordinate value in the equation and also y-coordinate value. So we can solve it.

As you know, </span>x=1 and y=2

y = 3x + c

2\quad =\quad 3\cdot 1+c\\ \\ 2\quad =\quad 3+c\\ \\ 2-3\quad =\quad c\\ \\ -1\quad =\quad c

We found c = -1 

Also in a line's equation, c is constant and it represents the line's y-intercept

So let's build the line's equation.

m=3 and c=-1

y= mx + c

y= 3x -1

We found the line's equation in this form, y= mx + c

Now let's turn it into this form, ax + by + c = 0

y\quad =\quad 3x-1\\ \\ y-3x\quad =\quad -1\\ \\ y-3x+1\quad =\quad 0\\ \\ -3x+y+1\quad =\quad 0

Final answers,

\boxed { y\quad =\quad 3x-1 }

and 

\boxed { -3x+y+1\quad =\quad 0 }

I hope this was clear enough :)




<span>


</span>
5 0
4 years ago
Read 2 more answers
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