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erma4kov [3.2K]
3 years ago
5

Select the two pairs of figures that are similar.

Mathematics
1 answer:
Orlov [11]3 years ago
3 0

Answer:

b+a+09=097

Step-by-step explanation:

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The solids are similar. Find the surface area S or the volume V of the smaller solid. If applicable, round your answer to the ne
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A source of laser light sends rays AB and AC toward two opposite walls of a hall. The light rays strike the walls at points B an
Nataly [62]

Answer:

The distance between the walls is 70 m.

Step-by-step explanation:

Given: A source of laser light is at point A on the ground between two parallel walls BE and CD . The walls are perpendicular to the ground that is

BE ⊥ ED and CD ⊥ ED

AB is a ray of light which strikes the wall on the left at point B which is 30 meters above the ground. that is BE = 30 m

AC is a ray of light which strikes the wall on the right at point C. The length of AC = 80 meters.

The ray AB makes an angle of 45 degrees with the ground that is m∠BAE = 45°

The ray AC makes an angle of 60 degrees with the ground that is m∠CAD = 60°

As shown is figure attached below.

WE have to find the distance between the walls that is Length of ED

Length of ED = EA + AD

Consider the Δ AEB,

Using trigonometric ratio,

\tan\theta=\frac{perpendicular}{base}

Here \theta=45^{\circ} , perpendicular = 30 m  and base we can find.

thus,

\tan 45^{\circ}=\frac{30}{EA}

We know \tan 45^{\circ}=1

thus, EA =  30 m

Consider the Δ AEB,

Using trigonometric ratio,

\cos\theta=\frac{base}{hypotenuse}

Here \theta=60^{\circ} , hypotenuse = 80 m  and base we can find.

thus, \cos 60^{\circ}=\frac{base}{80}

We know, \cos 60^{\circ}=\frac{1}{2}

thus, Base = 40 m

AD = 40 m

Thus, the distance between the walls that is the length of ED = 30 + 40 = 70 m

4 0
3 years ago
Solve 9x + 3 = -33 . PLEASE HELP ME IT WILL MAKE MY DAY​
ValentinkaMS [17]

:  \implies \sf 9x + 3 =  - 33

: \implies \sf 9x =  - 33 - 3

:  \implies \sf 9x =  - 36

:  \implies \sf x =  \dfrac{ - 36}{9}  =  - 4

\therefore  \sf x =  -4

8 0
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