Well first to find the mean you will have to add up all the numbers together.
5,299 is the total. After you have done that count how many numbers there are. There are 24 numbers. Divide 5,299 by 24 and you get about 220.8. So the mean is 220.8 To find the median number of jumps, write out all the numbers in order from least to greatest. I think you can do this part! The middle number is your answer. If there is no middle number, get the two numbers that are on each side of the middle and divide by 2. Hope I helped!
Tables are created by substitute a set of input values into the function to create outputs. The required table is as shown below
<em>x | y</em>
<em>0 -3 </em>
<em>1 -2.5</em>
<em>2 -2 </em>
<h3>Tables and values</h3>
Tables are created by substitute a set of input values into the function to create outputs
Using x = 0, 1 and 2 as the input values
Given the function
y = 1/2x - 3
If x = 0
y = 1/2(0) - 3
y = -3
If x = 1
y = 1/2(1) - 3
y = -2.5
If x = 2
y = 1/2(2) - 3
y = -2
Hence the required table is as shown below
x | y
0 -3
1 -2.5
2 -2
Learn more on tables and values here: brainly.com/question/12151322
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Answer:
2.54379284 hp.
Step-by-step explanation: Torque is defined as the engines rotational force. First we find the distance = m in equation- then we use the formula Power = work/time = 16.7/ 5 = 3.34 and Horsepower formula is given by. Horsepower = (Torque × Speed) / 5252. HP = (3.34 × 4000) / 5252. HP = 13360/5252. HP = 2.54379284 hp.
Given : W=4000 m=? h=20 m
Time of operation t =5 s
Work done in lifting a box W=mgh= ? ×12×20=4000 = m = 4000/240=16.6666667 = 16.7KG
Power required P= W/t = w/p = 120000/120 =1000 watts We divide 60/5 = 120 then divide by 10 = 12 (being g)
Answer:
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Step-by-step explanation:
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Answer: Kriz should pay $50,100 at the end of the term.
Step-by-step explanation:
If the interest is compunded quarterly, then the accumulated amount after t years will be:
, where P= principal value , r = rate of interest .
Given: P= 50,000 , r= 5% = 0.05, t= 4 years
Then,

Hence, Kriz should pay $50,100 at the end of the term.