Question

A line passes through the point (6,-6) and has a slope of 3/2. Write a equation in point-slope form for this line

Answer 1

Answer: $y+6=\frac{3}{2} (x-6)$

Step-by-step explanation:

use the equation $y-y_{1} =m(x-x_{1})$

we know the slope, y, and x, so plug in

$y-(-6)=\frac{3}{2} (x-(6))$

$y+6=\frac{3}{2} (x-6)$

Answer 2

Answer:

$y=\frac{3}{2}x-15$

Step-by-step explanation:

The point-slope equation is $y-y_{1} =m(x-x_{1} )$

Here our m is our slope which is $\frac{3}{2}$ and our $(x_{1},y_{1})$ point is (6, -6)

Plugging in these values to our equation gives us

y - (-6) = $\frac{3}{2}$(x - 6) → distribute the negative to the -6 on the left side and then distribute the $\frac{3}{2}$ to the x term and the -6 on the right side → y + 6 = $\frac{3}{2}x$ - 9 → then subtract the 6 from both sides → $y=\frac{3}{2} x-15$