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navik [9.2K]
3 years ago
15

Find the 7th term of a geometric sequence with t1 = 6 and r = 4.

Mathematics
2 answers:
Helen [10]3 years ago
8 0

To solve for the 7th term of a geometric sequence with t1 = 6 and r = 4, we use the following equation:

<span>
a(n) = a(1) r^(n-1)
a7 = (6) 4^(7-1)
a7 = 24576</span>

Hope this answers the question. Have a nice day. Feel free to ask more questions.

Montano1993 [528]3 years ago
6 0

Answer:

24,576.

Step-by-step explanation:

We have been given that first term of a geometric sequence is 6 and common ratio is 4. We are asked to find the 7th term of the sequence.

We know that a geometric sequence is in form a_n=a_1\cdot r^{n-1}, where,

a_n = nth term of sequence,

a_1 = 1st term of sequence,

r = common ratio.

Upon substituting a_1=6 and r=4 and n=7 in geometric sequence formula, we will get:

a_7=6\cdot(4)^{7-1}

a_7=6\cdot(4)^{6}

a_7=6\cdot 4,096

a_7=24,576

Therefore, the 7th term of the given geometric sequence would be 24,576.

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