Question

Find the 7th term of a geometric sequence with t1 = 6 and r = 4.

Answer 1

To solve for the 7th term of a geometric sequence with t1 = 6 and r = 4, we use the following equation:

a(n) = a(1) r^(n-1)
a7 = (6) 4^(7-1)
a7 = 24576

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Answer 2

Answer:

24,576.

Step-by-step explanation:

We have been given that first term of a geometric sequence is 6 and common ratio is 4. We are asked to find the 7th term of the sequence.

We know that a geometric sequence is in form $a_n=a_1\cdot r^{n-1}$, where,

$a_n$ = nth term of sequence,

$a_1$ = 1st term of sequence,

$r$ = common ratio.

Upon substituting $a_1=6$ and $r=4$ and $n=7$ in geometric sequence formula, we will get:

$a_7=6\cdot(4)^{7-1}$

$a_7=6\cdot(4)^{6}$

$a_7=6\cdot 4,096$

$a_7=24,576$

Therefore, the 7th term of the given geometric sequence would be 24,576.