I would say that they equally brought the same quantity. 3/4 is 3 out of 4, 2/3 is 2 out of 3. I just see that they both made equal effort.
Y=12 because the triangles have proportional side lengths
Answer:
Point P is in between points F and G.
Now, here we do not have the actual locations of F and G, so i will answer this in a general way.
Suppose that F is located at 0 and G is located at some value A.
Then the distance FG = A - 0 = A.
Now, the distance between F and P is:
Distance = (1/4)*FG = A/4
Then the location of P is equal to the location of F plus A/4
P = 0 + A/4
Now, writing this in a more general way:
P = F + FG/4
Answer:
This problem is incomplete, we do not know the fraction of the students that have a dog and also have a cat. Suppose we write the problem as:
"In Mrs.Hu's classroom, 4/5 of the students have a dog as a pet. X of the students who have a dog as a pet also have cat as a pet. If there are 45 students in her class, how many have both a dog and a cat as pets?"
Where X must be a positive number smaller than one, now we can solve it:
we know that in the class we have 45 students, and 4/5 of those students have dogs, so the number of students that have a dog as a pet is:
N = 45*(4/5) = 36
And we know that X of those 36 students also have a cat, so the number of students that have a dog and a cat is:
M = 36*X
now, we do not have, suppose that the value of X is 1/2 ("1/2 of the students who have a dog also have a cat")
M = 36*(1/2) = 18
So you can replace the value of X in the equation and find the number of students that have a dog and a cat as pets.
Answer:
divide through out by -8 :
Answer is b
