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DENIUS [597]
2 years ago
5

Yolanda has 2 gallons of water in a bucket. If she throws out 2/3 of water, how much water will shr have left?

Mathematics
2 answers:
Scorpion4ik [409]2 years ago
8 0
It will be left 1/7 I think it will work
aliina [53]2 years ago
8 0

Answer:

1.33333333333

Step-by-step explanation:

2-(2/3)= 1.33333333333

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Which coordinate divides the directed line segment from -10 At J to23 at K in the ratio of 2 to 1
CaHeK987 [17]

Answer:

What are the options?

5 0
3 years ago
Simplify the product using the distributive property. (-4h +2)(3h +7)
Alekssandra [29.7K]

Answer:

  A.  -12h² - 22h + 14

Step-by-step explanation:

(-4h +2)(3h +7) = -4h(3h +7) +2(3h +7) . . . . . . . (a +b)c = ac +bc

  = (-4h)(3h) + (-4h)(7) + (2)(3h) + (2)(7) . . . . . . . a(b +c) = ab +ac . . . (twice)

  = -12h² -28h +6h +14

  = -12h² -22h +14 . . . . . . . . collect terms

3 0
3 years ago
Suppose each runner ran at the rate given in the table above for 3.1 miles. How much time will elapse between the first place fi
Scilla [17]
You didn't include the table but I found this table for the same statement, so I will answer you based on the next table:

Runner         distance           time

Arabella        7,299 feet        561 seconds
Bettina          3,425 yards     13 minutes, 12 seconds
Chandra       8,214 feet        0,195 hours
Divya            1,62 miles        732 seconds

To answer the question you must find the rate for each runner and then calculate the time to run 3.1 miles at each rate.

First you need to convert the data to obtain the rate in miles per second.

These are the main conversion identities:

1 mile = 5280 feet

1 mile = 1760 yards

1 hour = 3600 seconds

1 hour = 60 minutes

1 minute = 60 seconds

Arabella:

rate: 7,229 feet / 561 seconds * (1 mile / 5280 feet)  =

= 0.00244 mile/second

Time to run 3.1 miles: V = d / t => t = d / V = 3.1 miles / 0.00244 mile/second = 1270 seconds

Bettina:

13 minutes + 12 seconds = 13*60 seconds +12 seconds = 792 seconds

rate = 3425 yards / 792 seconds * 1 mile / 1760 yards = 0.00246 mile/seconds

Time to run 3.1 miles = 3.1 miles / 0.00246 mile/second = 1260 seconds

Chandra:

rate = 8214 feet / 0.195 hours * 1 mile / 5280 feet * 1hour / 3600 seconds =

= 0.00222 seconds

Time = 3.1 mile / 0.00222 seconds = 0.389 hour = 1396 seconds

Divya:

rate = 1.62 miles / 732 seconds = 0.00221 seconds

Time = 3.1 mile / 0.00221 seconds = 1403 seconds

Now you can find the difference between fhe last and the first 1403 seconds - 1260 seconds = 143 seconds

That is equivalent to 2.38 seconds.
6 0
3 years ago
If a 100.8 kg cement bag had 20.35 kg removed from it, what is the new weight of the bag?
Snowcat [4.5K]
Just subtract 20.35 from 100.8
100.8 \: kg - 20.35 \: kg = 80.45 \: kg

if your bag weighs 100.8 kg and you scoop out 20.35 kg then weigh your bag it will be 80.45 bc u took out 20.35 kg of the cement to use. hope that explains it
8 0
3 years ago
Of the 1,640 students enrolled at a school, 50% come to school by bus, 35% come by car, and the rest of the students walk home.
ehidna [41]
So first we need to find what percent of the students walk to school. 

50 + 35 = 85% don't walk leaving only 15% that walk to school, 

To find the 15% percent that DO walk we multiply .15 by the total number of people. 

.15 x 1640 = 246 people walk to school 
3 0
3 years ago
Read 2 more answers
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