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ivann1987 [24]
3 years ago
11

10x+18<-2help me please!!!

Mathematics
2 answers:
grin007 [14]3 years ago
8 0
It is x=2 that is what it is


sergey [27]3 years ago
3 0
10x ∠-20
x∠-20/10

x∠-2

this is your answer
hope it helps
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Which of the following best describes the pattern in the diagram as you move
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Answer:

B because as you move from left to right the pattern increases by 1

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3 years ago
Kobe, A'mari and DJ are raising money for their football team to take a trip to San Diego. Kobe collected $18.50 more than A'mar
ira [324]

Answer:

So Kobe collected $42.15

Step-by-step explanation:

Kobe, A'mari and DJ are raising money for the football team to take a trip to San Diego.

Let x = amount which Kobe collected

Let y = amount which Amari collected

Let z= amount which Dj collected.

Kobe collected $18.50 more than A‘Mari. This means

x= y + 18.5 - - - - - - 1

DJ collected $12.25 less than Kobe

z = x-12.25 - - -- - - - - 2

Total sum collected by the 3 boys

= $95.70 This means

x + y+ z= 95.70 - -- - -- - -3

Put x = y + 18.5 in equation 3 and also

x= z+12.25 in equation 3

y + 18.5 + y+ z= 95.70

2y +z = 95.70-18.5 = 77.2

2y +z = 77.2 - - - - - -4

z + 12.25 + y+ z= 95.70

y +2z = 83.45 - - - - - -- - 5

Multiply equation 4 by 1 and equation 5 by 2

2y +z = 77.2

2y + 4z = 166.9

-3z = -89.7

z = 89.7/3= 29.9

Put z =29.9 in 2y+z = 77.2

2y +29.9= 77.2

2y = 77.2-29.9= 47.3

y = 47.3/2 = 23.65

Put y=23.65 and z = 29.9 in equation 3

x + 23.65+ 29.9= 95.70

x = 95.70-53.55

=$42.15

So Kobe collected $42.15

6 0
4 years ago
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Assuming this is symmetrical, point A and point B are direct opposites from the points on the same axis as them

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8 0
3 years ago
Hey does any body know how i can approximate 13 like this had this homework but it got late on me.​
Illusion [34]

Answer:

(see attachment)

To approximate the square root of 13:

Working from the top down...

Enter the number you are trying to approximate in the top box: \boxed{\sf \sqrt{13}}

Find the perfect squares directly below and above 13.

Perfect squares:  1, 4, 9, 16, 25, 36, ...

Therefore, the perfect squares below and above 13 are: 9 and 16

Enter these with square root signs in the next two boxes: \boxed{\sf \sqrt{9}} and  \boxed{\sf \sqrt{16}}  

Carry out the operation and enter  \boxed{\sf 3} and \boxed{\sf 4} in the next two boxes.

Enter the number you are trying to square root (13) in the top left box, the perfect square above it (16) in the box below, then the perfect square below it (9) in the two boxes to the right of these. Carry out the subtractions and place the numbers in the boxes to the right.

\dfrac{\boxed{\sf 13}-\boxed{\sf 9}}{\boxed{\sf 16}-\boxed{\sf 9}}=\dfrac{\boxed{\sf 4}}{\boxed{\sf 7}}

Now enter the number you are trying to square root (13) under the square root sign.  Place the square root of the perfect square below it (3) in the box to the right.  Copy the fraction from above (4/7).  Finally, enter this mixed number into a calculator and round to the nearest hundredth.

\sf \sqrt{13}=\boxed{\sf3}\dfrac{\boxed{\sf 4}}{\boxed{\sf 7}}=\boxed{\sf3.57}

7 0
2 years ago
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