Answer:
6375 ≤ P < 6385
Step-by-step explanation:
When rounding to the nearest 10, the unit value is either rounded to 1 and added to the tens value (if value is greater than or equal to 5) or rounded to 0 (if less Than 5)
Hence, the lower limit of a number p which gives 6380 when rounded to the nearest ten would be 6375 ;
The upper limit of the number p in other to give 6380 when rounded to the nearest 10 will be 6384 (< 6385)
Answer:
10 times
Step-by-step explanation:
there are a total of 200 coins
each time he makes a selection the probability of selecting a dime is 40/200 or 1/5
if he makes 50 selections, the probability is 1/5(50) which is 10 times
To find the maximum or minimum value of a function, we can find the derivative of the function, set it equal to 0, and solve for the critical points.
H'(t) = -32t + 64
Now find the critical numbers:
-32t + 64 = 0
-32t = -64
t = 2 seconds
Since H(t) has a negative leading coefficient, we know that it opens downward. This means that the critical point is a maximum value rather than a minimum. If we weren't sure, we could check by plugging in a value for t slightly less and slighter greater than t=2 into H'(t):
H'(1) = 32
H'(3) = -32
As you can see, the rate of change of the object's height goes from increasing to decreasing, meaning the critical point at t=2 is a maximum.
To find the height, plug t=2 into H(t):
H(2) = -16(2)^2 +64(2) + 30 = 94
The answer is 94 ft at 2 sec.
Answer:
See explaination for the details of the answer
Step-by-step explanation:
Defect per opportunity DPO = defects/ no. of opportunities = 2/25 = 0.08
Defect per million opportunities
DPMO = DPO * 1 million
DPMO = 0.08 * 1 million = 80,000
six sigma = 2.9, take the dpmo at higher level if not exact 80800 for 2.9
Answer:
C
Step-by-step explanation:
Lucky guess I guess.
