40 cm long. hope this helps
Answer:
I'm not sure if it is correct but i hope it helps you
Step-by-step explanation:
So you subtract 25 and 15 and you will get 10
then you add 65 and 5 and you will get 70
you add 45 and 20 and you will get 65
Answer:
1 3/4 = 7/4 = 1.75
Step-by-step explanation:
The process to arrive to the solution is explained in the pictures below.
Tyler needed to convert the mixed fraction
2 1/2 = (4+1)/2 = 5/2
If we multiply by 2 numerator and denominator
5*2/2*2 = 10/4
We substract
10/4 - 3/4 = 7/4 = 1.75
Answer:
3.940201X 10^115
Step-by-step explanation:
2^3x (2x2x2x2x2x2x2)
2^3x128
2^384
3.940201 x 10^115
Answer:
Total area = 237.09 cm²
Step-by-step explanation:
Given question is incomplete; here is the complete question.
Field book of an agricultural land is given in the figure. It is divided into 4 plots. Plot I is a right triangle, plot II is an equilateral triangle, plot III is a rectangle and plot IV is a trapezium, Find the area of each plot and the total area of the field. ( use √3 =1.73)
From the figure attached,
Area of the right triangle I = 
Area of ΔADC = 
= 
= 
= 
= 
= 30 cm²
Area of equilateral triangle II = 
Area of equilateral triangle II = 
= 
= 73.0925
≈ 73.09 cm²
Area of rectangle III = Length × width
= CF × CD
= 7 × 5
= 35 cm²
Area of trapezium EFGH = 
Since, GH = GJ + JK + KH
17 = 
12 = 
144 = (81 - x²) + (225 - x²) + 2
144 - 306 = -2x² + 
-81 = -x² + 
(x² - 81)² = (81 - x²)(225 - x²)
x⁴ + 6561 - 162x² = 18225 - 306x² + x⁴
144x² - 11664 = 0
x² = 81
x = 9 cm
Now area of plot IV = 
= 99 cm²
Total Area of the land = 30 + 73.09 + 35 + 99
= 237.09 cm²