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enot [183]
4 years ago
6

the estimated probability of a football players scoring a touchdown during a particular game is 26% is several simulations of a

football player playing two games were performed in what percentage of the simulations would the football player be most likely to get a touchdown in each of the two games
Mathematics
1 answer:
joja [24]4 years ago
4 0
Given
   26% = several simulations of a football player playing two games 
Find the percentage of the simulations in each of the two games

2x = .26

2x = .26
----    -----
 2       2

x = .13 * 100
x= 13 

The answer is 13% of simulations would the football player be most likely to get a touchdown in each of the two games. 


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What is 0.0000001 converted to the tenth power
jenyasd209 [6]

this would look like this: 0.0000001^10

If we were to do 0.0000001*0.0000001 it would be 0.00000000000010

We doubled the zeroes and moved the one up. Continue on until you reach the tenth power.

6 0
3 years ago
Find the mean 35 40 12 16 25 10
ruslelena [56]

Answer: Mean = 23

Step-by-step explanation:

<u>Given information:</u>

35, 40, 12, 16, 25, 10

<u>Given formula:</u>

Mean~=~\frac{Sum~of~terms}{Number~of~terms}

<u>Substitute values into the formula</u>

Mean~=~\frac{35~+~40~+~12~+~16~+~25~+~10}{6}

<u>Combine like terms</u>

Mean~=~\frac{75~+~28~+~35}{6}

Mean~=~\frac{103~+~35}{6}

Mean~=~\frac{138}{6}

<u>Simplify the fraction</u>

\Large\boxed{Mean=23}

Hope this helps!! :)

Please let me know if you have any questions

4 0
2 years ago
An equation is shown below: 3(2x − 7) = 9
Katen [24]

Answer:

1 solution

Step-by-step explanation:

3(2x-7)=9

dustribute: (3)(2)+(3)(-7x)=9

6+-21x=9

subtract 6 from both sides: -21x=3

Divide both sides by -21: x=-1/7

so your 1 solution is x = - 1/7

3 0
2 years ago
Helpp!!<br> Simplify : [( 4 1/6 + 2 1/3 ) ÷ 4 1/3 ] - 1 1/2
Nadusha1986 [10]

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{0}}}}}

Step-by-step explanation:

\sf{ [ (4 \frac{1}{6}  + 2 \frac{1}{3} )  \div 4 \frac{1}{3}] -  1\frac{1}{2} }

Convert the mixed numbers into improper fraction

\longrightarrow{ \sf{ [ ( \frac{25}{6}  +  \frac{7}{3} ) \div  \frac{13}{3}] -  \frac{3}{2}}}

Add the fractions : 25 / 6 and 7 / 3

While performing addition or subtraction of unlike fractions, you have to express the given fractions into equivalent fractions of common denominator and add or subtract as we do with like fraction.

To do so, first take the L.C.M of 6 and 3 which results to 6

\longrightarrow\sf{ [( \frac{25 + 7 \times 2}{6} ) \div  \frac{13}{3} ] -  \frac{3}{2}}

\longrightarrow{ \sf{ [( \frac{25 + 14}{6} )  \div  \frac{13}{3}  ] -  \frac{3}{2} }}

\longrightarrow{ \sf{ [ \frac{39}{6}  \div  \frac{13}{3}] -  \frac{3}{2} }}

Multiply the dividend by the reciprocal of the divisor.

Reciprocal of any number or fraction can be obtained by interchanging the position of numerator and denominator

\longrightarrow{ \sf{ [  \frac{39}{6}  \times  \frac{3}{13} ] -  \frac{3}{2}}}

To multiply one fraction by another, multiply the numerators for the numerator and multiply the denominators for its denominator and reduce the fraction obtained after multiplication into lowest term

\longrightarrow{ \sf{ [  \frac{39 \times 3}{6 \times 13} ] -  \frac{3}{2}}}

\longrightarrow{ \sf{ [  \frac{117}{78}  ] -  \frac{3}{2} }}

\longrightarrow{ \sf{ \frac{3}{2}  -  \frac{3}{2} }}

While performing the addition or subtraction of like fractions , you just have to add or subtract the numerator respectively in which the denominator is retained same

\longrightarrow{ \sf{ \frac{3 - 3}{2} }}

Subtract 3 from 3

\longrightarrow{ \sf{ \frac{0}{2}}}

Divide 0 by 2

\longrightarrow{ \sf{0}}

Hope I helped!

Best regards!

3 0
3 years ago
How do I get the answer to m+4=13/2
Kaylis [27]
M=13/2 - 4

\frac{13}{2} - \frac{4}{1} =  \frac{13-8}{2} = \frac{5}{2} =2.5

m=2.5
4 0
3 years ago
Read 2 more answers
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