Answer:
3x^2-6x -3
Step-by-step explanation:
(2x^2-5x+1)+(x^2-x-4)
we sum all coefficient according to the exponent of the variable
2x^2-5x+1+x^2-x-4 = 3x^2-6x -3
Answer:
D. ![xy\sqrt[3]{9y}](https://tex.z-dn.net/?f=xy%5Csqrt%5B3%5D%7B9y%7D)
Step-by-step explanation:
![\sqrt[3]{9x^3y^4}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B9x%5E3y%5E4%7D)
![\sqrt[3]{9}\sqrt[3]{x^3}\sqrt[3]{y^4}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B9%7D%5Csqrt%5B3%5D%7Bx%5E3%7D%5Csqrt%5B3%5D%7By%5E4%7D)
The
cancels out to become x:
![\sqrt[3]{9}x\sqrt[3]{y^4}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B9%7Dx%5Csqrt%5B3%5D%7By%5E4%7D)
Split the 
![\sqrt[3]{9}x\sqrt[3]{y^3}\sqrt[3]{y^1}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B9%7Dx%5Csqrt%5B3%5D%7By%5E3%7D%5Csqrt%5B3%5D%7By%5E1%7D)
![\sqrt[3]{y^3} =y](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7By%5E3%7D%20%3Dy)
![xy\sqrt[3]{9} \sqrt[3]{y}](https://tex.z-dn.net/?f=xy%5Csqrt%5B3%5D%7B9%7D%20%5Csqrt%5B3%5D%7By%7D)
Put the cube root of y and cube root of 9 together:
![xy\sqrt[3]{9y}](https://tex.z-dn.net/?f=xy%5Csqrt%5B3%5D%7B9y%7D)
1 and 2 i can't answer without proper data.
3. x+2x+2x+6 = 86
5x+6 = 86
-6 -6
5x = 80
x = 16
Side one: x is 16
Side two: 2x is 2(16) = 32
Side three: 2x+6 is 38
Answer:
The correct option is (B)
(B) x-y = 6 , 3x+4y = 4
Step-by-step explanation:
As we can see in the graph given below, both lines intersect at (4, -2), which should be the solution of given equations:
Find the values of x and y for (B);
x - y = 6 ⇒ (i)
3x + 4y = 4 ⇒ (ii)
Lets consider equation (i)
x - y = 6
x = 6 + y
Substitute in equation (ii)
3(6+y) + 4y = 4
18 + 3y + 4y = 4
7y = -14
y = -2
Substitute in equation (i)
x - (-2) = 6
x + 2 = 6
x = 6 - 2
x = 4
As solution of part C is also (4, -2), it represents the graph
You can also find the (x, y) for other options the similar way, which will show you they don't have the same value