Answer:
A. $10,500
Explanation:
FV of IDNA:
Book value $ 15,000
Revalued plant assets ($25,000)
license agreements
$30,000
Intangible assets $50,000
$ 70,000
Non-controlling interest valued at the date of acquisition, following the alternative method allowed by IFRS = 15% * 70,000 = $10,500.
It must be debatable. Hope this helps
<span>n/2 = average number of items to search.
Or more precisely (n+1)/2
I could just assert that the answer is n/2, but instead I'll prove it. Since each item has the same probability of being searched for, I'll simulate performing n searches on a list of n items and then calculate the average length of the searches. So I'll have 1 search with a length of 1, another search looks at 2, next search is 3, and so forth and so on until I have the nth search looking at n items. The total number of items looked at for those n searches will be:
1 + 2 + 3 + 4 + ... + n
Now if you want to find the sum of numbers from 1 to n, the formula turns out to be n(n+1)/2
And of course, the average will be that sum divided by n. So we have (n(n+1)/2)/n = (n+1)/2 = n/2 + 1/2
Most people will ignore that constant figure of 1/2 and simply say that if you're doing a linear search of an unsorted list, on average, you'll have to look at half of the list.</span>
On Monday and Tuesday, the process appears to be out of control.
<u>Explanation</u>:
- There are five days Monday, Tuesday,Wednesday, Thursday and Friday. Monday and Tuesday have weight up to 21. Wednesday weights up to 21.
- Thursday and Friday weigh up to 20. Except for Monday and Tuesday, all the days have packaged up to the value of 21. So Monday and Tuesday are the days that appear to be out of control.
- On checking the package for each day he came to know that Monday and Tuesday have process out of control.
Answer:
<em>The answer is 17.01 minutes</em>
Explanation:
<em>Given that:</em>
<em>The learning rate (r) = 85% = 0.85</em>
<em> T₃₂= 23.52 minutes</em>
<em>By applying the learning curve formula</em>
<em>Thus,</em>
<em>Tₙ = T₁ nᵇ</em>
<em>Where b represent ln(r)/ln2</em>
<em>b = ln( 0.85)/ln2 = -0.2344</em>
<em>23.55 = T₁ * (32)^-0.2344</em>
<em>T₁ = 23.55 * (32)^0.2344</em>
<em>Now,</em>
<em>T₁₂₈ = T₁ (128)^ - 0.2344</em>
<em>= 23.55 * (32)^0.2344 * (128)^ - 0.2344</em>
<em>=17.01 minutes</em>
