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Alenkasestr [34]
3 years ago
13

at a pizza shop, 75% of the customers order pizza, 20% of the customers order salad, and 15% of the customers order a pizza and

a salad. If a customer is chosen at random, what is the probability that he or she orders either of pizza or salad?
Mathematics
2 answers:
slava [35]3 years ago
8 0

Answer:

There would be a 65% chance of picking a customer who orders one or the other.

Step-by-step explanation:

In order to find this, we first must find the percentage that orders only pizza. We can do this by subtracting the overlap from the total number.

75% - 15% = 60%

We need to do the same thing for salad.

20% - 15% = 5%

Now that we have the percentages who ordered just one or the other, we can add them together to get the total percentage who got either one or the other.

60% + 5% = 65%

timama [110]3 years ago
7 0
Most likely is the answer
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2 years ago
A rectangle has a perimeter of 204 feet. It's length is six feet longer than twice it's width. If L stands for the length of the
Ratling [72]

Answer:

L = 70

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Step-by-step explanation:

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7 0
3 years ago
Can someone help me please??
dem82 [27]
Add all the sides together
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