So I think you have to find 11% of 24 and that is 11/100 x 24 = 2.64$. Then you reduce it to the real price 24-2.64= 21.36$ (the new prize). I might be completly wrong but I hope this helps
5^(x+7)=(1/625)^(2x-13)
We move all terms to the left:
5^(x+7)-((1/625)^(2x-13))=0
Domain of the equation: 625)^(2x-13))!=0
x∈R
We add all the numbers together, and all the variables
5^(x+7)-((+1/625)^(2x-13))=0
We multiply all the terms by the denominator
(5^(x+7))*625)^(2x+1-13))-((=0
We add all the numbers together, and all the variables
(5^(x+7))*625)^(2x-12))-((=0
We add all the numbers together, and all the variables
(5^(x+7))*625)^(2x=0
not sure if this is right :/
Answer:
largest to smallest is.
<h2>23,14,12</h2>
Step-by-step explanation:
hope this helps
Is there a picture of the ramp?
The question is incomplete:
Bella and Heather put some money into their money boxes every week. The amount of money (y), in dollars, in their money boxes after a certain amount of time (x), in weeks, is shown by the equations below: Bella: y = 25x + 60 Heather: y = 30x + 10 After how many weeks will Bella and Heather have the same amount of money in their money boxes, and what is that amount?
10 weeks, $10
10 weeks, $310
9 weeks, $310
310 weeks, $10
Answer:
10 weeks, $310
Step-by-step explanation:
As the statement indicates, you have the following equations:
y=25x+60
y=30x+10
where:
y= the amount of money
x= the amount of time in weeks
You can equalize the expressions and isolate x to find the number of weeks after which Bella and Heather will have the same amount of money:
25x+60=30x+10
60-10=30x-25x
50=5x
x=50/5= 10
After this, you can replace the value of x in any of the equations to find the amount of money that they will have after 10 weeks:
-y=25(10)+60=310
-y=30(10)+10= 310
According to this, the answer is 10 weeks, $310.
