Answer:
The first pair shows equivalent expressions.
Step-by-step explanation:
3(x+2), you would have to distribute 3 among x and 2, also known as expanding the expression. So you'd do 3*x + 3*2, which equals 3x+6
The first equation is 3(x+2)=3x+6
Therefore, the first pair shows equivalent expressions.
Answer:
Step-by-step explanation:
Scalene triangle are the triangle with no side are equal in length also each angle have different measure.
As given there are two scalene triangle, which are similar.
∴ Side of both the triangle will be propotionally equal.
Scale is given for both the triangle, which is 5:2.
We know, scale factor= ratio of the side.
Looking the option provided, we see
As the sides of both the triangle is propotionally equal
Hence, .
Answer:
∠A = 88°
∠B = 92°
∠C = 88°
∠D = 92°
Step-by-step explanation:
∠A + ∠B = 180°
(2x + 4) + (3x - 34) = 180
reduce:
5x - 30 = 180
5x = 210
x = 42
∠A = 2(42) + 4 = 88°
∠B = 3(42) -34 = 92°
∠C = ∠A = 88°
∠D = ∠B = 92°
Answer:
The probability of selecting a students that drinks sugar free red bull is <em><u>0.1</u></em>
Step-by-step explanation:
In this question, we are concerned with calculating probability that out of the 120 students interviewed, a student chosen at random drinks sugar free red bull.
Mathematically, the probability is = number of students that drinks sugar free red bull/Total number of students interviewed
We know the total number of students interviewed, but we do not know the number of students that drink sugar free red bull.
Now looking at the question, we can see that all the students interviewed has the choice of having only to drinks, monster or red bull.
Since 72 students drink monster, the number of students that take red bull = 120 - 72 = 48
Now from this 48, we have a ratio. The ratio of regular type to sugar free is 3:1. The number taking sugar free is thus 1/4 × 48 = 12 students
The probability of choosing a student that drinks sugar free red bull is thus 12/120 = 1/10 = 0.1
V=<span>π r^(2)h
you put the number in the place of the R and H</span>
