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Mice21 [21]
3 years ago
14

A bouncing ball reaches a height of 54 inches at its first peek 36 inches at its second peak and 24 inches at its third peak. Wh

ich formula represents this scenario?
Mathematics
2 answers:
irina1246 [14]3 years ago
7 0

Answer:

Geometric sequence

=54(2/3)^(n-1)

Step-by-step explanation:

Given that a ball is bounced and get up and again hits the ground and bounces up, and so on.

The first height after first hit = 54 inches

Next second peak = 36 inches

III peak = 24 inches

The second peak is 2/3 of first height

and third peak is 2/3 of second height

Thus there is a pattern of geometric sequences such that each peak is 23 of initial peak

IN general nth peak = 54(2/3)^(n-1)

faust18 [17]3 years ago
6 0

Answer:

If the possible answers are what other questions like this have up, then the answer is indeed B.

Good luck and have a great day :)

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Calculate P(A or B) where A and B are mutually exclusive events and P(A) = 1 and P(B) =
34kurt

Answer:

  1

Step-by-step explanation:

If A and B are mutually exclusive and A is certain to happen, then B is certain to never happen, so P(B) = 0. The probability of either of two mutually exclusive events is the sum of their individual probabilities:

  P(A or B) = P(A) +P(B) = 1 + 0

  P(A or B) = 1

3 0
3 years ago
Question Help When purchasing bulk orders of​ batteries, a toy manufacturer uses this acceptance sampling​ plan: Randomly select
horrorfan [7]

Answer:

The probability is P(X  \le 2 ) = 0.9072

The company will accept 90.72% of the shipment and will reject (100 -90.72) =  9.2\% of the shipment , so many of the shipment are rejected

Step-by-step explanation:

From the question we are told that

   The  sample size is  n =  36

   The  proportion that did not meet the requirement is  p =  0.03

Generally the probability that the whole shipment is accepted is equivalent to the probability that there is at most 2 batteries that do not meet the requirement , this is mathematically represented as

     P(X  \le 2 ) = [ P(X =  0 ) +  P(X =  1 ) + P(X = 0)]

=>   P(X  \le 2 ) = [ [^{n}C_0 * (p)^{0} *(1-p)^{n-0} ] +  [^{n}C_1 * (p)^{1} *(1-p)^{n-1} ] +  [^{n}C_2 * (p)^{2} *(1-p)^{n-2} ]]

Here C stands for Combination (so we will be making the combination function in our  calculators )

So

=> P(X  \le 2 ) = [ [^{36}C_0 * (0.03)^{0} *(1-0.03)^{36-0} ] +  [^{36}C_1 * (0.03)^{1} *(1-0.03)^{36-1} ] +  [^{36}C_2 * (0.03)^{2} *(1-0.03)^{36-2} ]]

=> P(X  \le 2 ) = [ [1 * 1 * 0.3340  ] +  [36* 0.03 *0.3444 ] +  [630 * 0.0009 *(0.355 ]]

=>P(X  \le 2 ) = 0.9072

The company will accept 90.72% of the shipment and will reject (100 -90.72) =  9.2\% of the shipment , so many of the shipment are rejected

 

8 0
3 years ago
I need help sorry for bothering everyone.
Paladinen [302]

Answer:

Look at the picture down below :)))

Step-by-step explanation:

I just took the test and I got the correct answers, hope this helps!

3 0
2 years ago
Read 2 more answers
Molly is wrapping up parts of sandwiches to sell at her sandwich cart. She cuts each sandwich into fourths and then wraps each f
Alisiya [41]

her mistake was that she was counting all the fourths as a whole sandwich when she really wraped up four sandwiches in total because 16 divided by 4 which is how many she cut it up into is 4 whole sandwiches
5 0
3 years ago
Describe 2 ways you could evaluate 37% of the sum of 27 3/5 and 15/9  
miskamm [114]
First way is create an equation like this:
0.37(27 \frac{3}{5}+ \frac{15}{9}) 
and calculating it.
Second way is to find 37% of each number and then add it
0.37*27 \frac{3}{5} + 0.37* \frac{15}{9}
In both cases the result is 10.829
3 0
3 years ago
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