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JulijaS [17]
3 years ago
15

Find the value of x in each case: Pls answer as fast as possible Thank You!!!!!!!

Mathematics
1 answer:
ycow [4]3 years ago
6 0

m\angle AEB+4x=180^o\to m\angle AEB=180^o-4x\\\\\angle DEB=2x+\angle AEB\ \text{and}\ \angle EBC=6x\ \text{are Alternate Interior Angles}\\\\\text{Alternate Interior Angles are congruent (have the same measure)}\\\\\text{Therefore we have the equation:}\\\\m\angle DEB=m\angle EBC\\\\2x+(180^o-4x)=6x\\\\2x+180^o-4x=6x\\\\(2x-4x)+180^o=6x\\\\-2x+180^o=6x\qquad|\text{add 2x to both sides}\\\\180^o=8x\qquad|\text{divide both sides by 8}\\\\22.5^o=x\to x=22.5^o

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vovangra [49]
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Someone please help me? Answe is NOT 4/7 , tried that already
pishuonlain [190]
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3 years ago
Let ​f(x)equals=33xminus−​1, ​h(x)equals=startfraction 7 over x plus 5 endfraction 7 x+5 . find ​(hcircle◦​f)(66​).
Ronch [10]
\bf \begin{cases}
f(x)=3x-1\\
h(x)=\cfrac{7}{x+5}\\\\
(h\circ f)(x)=h(~~f(x)~~)
\end{cases}
\\\\\\
f(66)=3(66)-1\implies \boxed{f(66)=197}
\\\\\\
\stackrel{h(~~f(x)~~)}{h(~~f(66)~~)}\implies \stackrel{h(~~f(66)~~)}{h\left(~~\boxed{197}~~ \right)}=\cfrac{7}{\boxed{197}+5}\implies h\left(~~\boxed{197}~~ \right)=\cfrac{7}{202}
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