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3 years ago

The total of 8 and the product of x and 2

Mathematics

1 answer:

vagabundo [1.1K]3 years ago

5 0

Answer:

8+2x

Step-by-step explanation:

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What is the answer to<br> -2a-9=6a+15

timurjin [86]

Answer:

$a=-3$

Step-by-step explanation:

$-2a-9=6a+15$

Add 9 to both sides:

$-2a-9+9=6a+15+9$

$-2a=6a+24$

Subtract 6a from both sides:

$-2a-6a=6a+24-6a$

$-8a=24$

Divide both sides by -8:

$\frac{-8a}{-8}=\frac{24}{-8}$

$a=-3$

4 0

3 years ago

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Solve for x:−2(x+9)=−1(x+−1)+2

Stella [2.4K]

Answer:

Step-by-step explanation:

expanding the bracket, we would have

-2x -18 = -x+1+2

-2x+x= 3 +18

-x=21

x=-21

6 0

3 years ago

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So this is for my geometry I'm trying to work on my review and I'm hoping that maybe one of you guys out here could help me with

alukav5142 [94]

Sorry it’s not that neat but I think the answer would be in the exact surd form root 233

7 0

2 years ago

Find the solution of the differential equation that satisfies the given initial condition. y' tan x = 3a + y, y(π/3) = 3a, 0 &lt

Paladinen [302]

Answer:

$y(x)=4a\sqrt{3}* sin(x)-3a$

Step-by-step explanation:

We have a separable equation, first let's rewrite the equation as:

$\frac{dy(x)}{dx} =\frac{3a+y}{tan(x)}$

But:

$\frac{1}{tan(x)} =cot(x)$

So:

$\frac{dy(x)}{dx} =cot(x)*(3a+y)$

Multiplying both sides by dx and dividing both sides by 3a+y:

$\frac{dy}{3a+y} =cot(x)dx$

Integrating both sides:

$\int\ \frac{dy}{3a+y} =\int\cot(x) \, dx$

Evaluating the integrals:

$log(3a+y)=log(sin(x))+C_1$

Where C1 is an arbitrary constant.

Solving for y:

$y(x)=-3a+e^{C_1} sin(x)$

$e^{C_1} =constant$

So:

$y(x)=C_1*sin(x)-3a$

Finally, let's evaluate the initial condition in order to find C1:

$y(\frac{\pi}{3} )=3a=C_1*sin(\frac{\pi}{3})-3a\\ 3a=C_1*\frac{\sqrt{3} }{2} -3a$

Solving for C1:

$C_1=4a\sqrt{3}$

Therefore:

$y(x)=4a\sqrt{3}* sin(x)-3a$

3 0

3 years ago

Nilai dari x memenuhi pertidaksamaan [x-1]<2

slega [8]

Answer:

Step-by-step explanation:

4 0

3 years ago

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