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3 years ago

Find the mean mode median,range 5.4, 3, 4.2, 9, 2.1, 3, 4.2

Mathematics

1 answer:

RideAnS [48]3 years ago

7 0

Range = 6.9
mode = 4.2
median= 3

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Rearrange y= 2(x-a)/x to make x the subject

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110% of 90 is what number a?

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Of the following data, 17, 20,14,5,30,13,6, and 5 find the mean median, and mode

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3 years ago

A market surveyor wishes to know how many energy drinks teenagers drink each week. They want to construct a 98% confidence inter

frosja888 [35]

Answer:

The minimum sample size required to create the specified confidence interval is 1024.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.98}{2} = 0.01$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.01 = 0.99$ , so $z = 2.327$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

What is the minimum sample size required to create the specified confidence interval

This is n when $M = 0.08, \sigma = \sqrt{1.21} = 1.1$ .

$M = z*\frac{\sigma}{\sqrt{n}}$

$0.08 = 2.327*\frac{1.1}{\sqrt{n}}$

$0.08\sqrt{n} = 2.327*1.1$

$\sqrt{n} = \frac{2.327*1.1}{0.08}$

$(\sqrt{n})^{2} = (\frac{2.327*1.1}{0.08})^{2}$

$n = 1024$

The minimum sample size required to create the specified confidence interval is 1024.

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3 years ago