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dimulka [17.4K]
3 years ago
8

15 POINTS!! WILL MARK BRAINLIEST!!! Suppose you draw one card from a standard deck of 52 cards. A standard deck of cards has 4 o

f each type of card, so the deck contains 4 kings and 4 queens. What is the probability that the card is a king or a queen? Explain.
Mathematics
1 answer:
Trava [24]3 years ago
5 0

Answer:

A standard deck of cards has 52 cards.

probability of king is 4/52 and probability of a queen is 4/52

so if you do 4/52 + 4/52 = 8/52

8/52 in simplest form is 2/13

Step-by-step explanation:

Hope this helps Have a nice day

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(x-1)(x-9)
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2 years ago
The perimeter of a regular octagon is 55.2 mm. Write and solve an equation to determine the length of each side of the octagon.
Katena32 [7]

Answer:

6.9

Step-by-step explanation:

An octagon has 8 sides so:

55.2=8*x

x=55.2/8=6.9

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2 years ago
To play basketball with her friends, Evangeline needs to pump air in her ball, which is completely deflated. Before inflating it
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Answer:

ρ_air = 0.15544 kg/m^3

Step-by-step explanation:

Solution:-

- The deflated ball ( no air ) initially weighs:

                             m1 = 0.615 kg

- The air is pumped into the ball and weight again. The new reading of the ball's weight is:

                            m2 = 0.624 kg

- The amount of air ( mass of air ) pumped into the ball can be determined from simple arithmetic between inflated and deflated weights of the ball.

                           m_air = Δm = m2 - m1

                           m_air = 0.624 - 0.615

                           m_air = 0.009 kg

- We are to assume that the inflated ball takes a shape of a perfect sphere with radius r = 0.24 m. The volume of the inflated ( air filled ) ball can be determined using the volume of sphere formula:

                         V_air = 4*π*r^3 / 3

                         V_air = 4*π*0.24^3 / 3

                         V_air = 0.05790 m^3  

 

- The density of air ( ρ_air ) is the ratio of mass of air and the volume occupied by air. Expressed as follows:

                         ρ_air = m_air / V_air

                         ρ_air = 0.009 / 0.05790

Answer:            ρ_air = 0.15544 kg/m^3                      

4 0
2 years ago
Read 2 more answers
Shania is making a scale diagram of the badminton court at the community center. She uses a scale of 1 centimeter to 0.5 meter t
Eva8 [605]
The answer is 81.74 meters
5 0
3 years ago
As a​ follow-up to a report on gas​ consumption, a consumer group conducted a study of SUV owners to estimate the mean mileage f
kondor19780726 [428]

Answer:

The 95​% confidence interval estimate for the mean highway mileage for SUVs is (18.29mpg, 20.91mpg).

Step-by-step explanation:

Our sample size is 96.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

df = 96-1 = 95

Then, we need to subtract one by the confidence level \alpha and divide by 2. So:

\frac{1-0.95}{2} = \frac{0.05}{2} = 0.025

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 95 and 0.025 in the t-distribution table, we have T = 1.9855.

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

s = \frac{5.6}{\sqrt{96}} = 0.57

Now, we multiply T and s

M = T*s = 1.9855*0.57 = 1.31

For the lower end of the interval, we subtract the mean by M. So 19.6 - 1.31 = 18.29

For the upper end of the interval, we add the mean to M. So 19.6 + 1.31 = 20.91

The 95​% confidence interval estimate for the mean highway mileage for SUVs is (18.29mpg, 20.91mpg).

8 0
3 years ago
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