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Montano1993 [528]
3 years ago
8

Can You help me with this question please. Thanks In Advance.

Mathematics
1 answer:
Andreas93 [3]3 years ago
6 0

The correct answer is y = - 5/2x - 3 or known as D.

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The point (–5, 6) is located in which quadrant?
kolbaska11 [484]
Quadrant 1 is the answer. quadrant 2 is to the right of quadrant 1 and quadrant 3 is below quadrant 1
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A(x+b)=c solve for x
ValentinkaMS [17]
A(x + b) = c
x+b = c / A
x = c/A - b

Hope this helps!

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3 years ago
Was it evaluated correctly?<br>Explain your reasoning​
Andreyy89
Yes, 4^2 x 3^3 = 144 and from here on out it’s just 12 and 144 which the 12 goes into 144 12 times
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in 2012, the general social survey included a question that asked participants how many hours they worked a week. do males work
Agata [3.3K]

Using sampling concepts, it is found that this is an example of independent samples.

  • For dependent samples, there is a paired measurement for one set of items.
  • For independent samples, separate measurements are made on two different sets, that is, the value on one sample reveal no information about the values on the other sample.

In this problem, there are two samples, the sample composed of male workers and the one composed of female workers, and separate measurements are taken, hence, it is an independent sample.

A similar problem is given at brainly.com/question/23106151

4 0
2 years ago
A new pop-up restaurant serving high-end street tacos just opened and is expected to have high demand based on the chef's prior
Harman [31]

Answer:

1. c

2. f

3. d

Step-by-step explanation:

This type of queuing model is an example of "single-channel, single-phase" process.

However, from the information given:

The inter-arrival rate = 10 customers per hour

Arrival time = 6 minutes

Service time = 5 minutes

∴

utilization = service time/arrival time

= 5/6

Time on queue T_q = p \times \dfrac{utilization }{1 - utilization} \times \dfrac{Cv_a^2 -Cv_b^2}{2}

T_q = 5 \times \dfrac{5/6 }{1 -5/6} \times \dfrac{(2.58^2 -0.75^2)}{2}

T_q = 25 \times 3.60945

T_q = 90.24 \\ \\ T_q \simeq 90 \ mins

Thus, customer waiting in the queue line is;

= \dfrac{T_q}{q}  \\ \\ = \dfrac{90}{6} \\ \\ \mathbf{=15}

Thus, new customers will have to wait in a total time of;

= waiting time + service time

= 90 + 5

= 95 minutes.

4 0
3 years ago
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