Answer:
Step-by-step explanation:
Can you upload another picture?
Let
, where
and let
be any real constant.
Given this definition of scalar multiplication, we can see right away that there is no identity element
such that
because
Answer: A
Step-by-step explanation:
The first thing we need to do is to make sure our equation is in standard form. The given equation is not in standard form.
3x²-2x=0
Now that the equation is in standard form, we can find our A, B, C to see which quadratic equation is correct.
A=3
B=-2
C=0
We can automatically eliminate D because the first value is -3 when it is supposed to be -(-2). Also, the denominator is supposed to be 2a. We know that A=3. The denominator should be 2(3), not 2(-2).
Next, we can eliminate B and C. For the 4ac, we know it has to be 4(3)(0) because A=3 and C=0. B and C have given 4(3)(2) and 4(3)(1), respectively. This does not match A=3 and C=0.
Therefore, A is the correct answer.
Answer:
9
Step-by-step explanation:
Find all the prime factors of the three numbers. pick up the common factors, ONCE, then pick up the non-common factors one by one, multiply the factors, the product is the least common factor.
example: the least common multiple of 6, 8, and 15
6=2*3
8=2*2*2
15=3*5
Note: do not write 8 into 4*2, because 4 is not a prime number. you have to break the number down to prime factors only.
Notice that 6 and 8 have a common factor 2, so pick up the 2;
6 and 15 have a common factor of 3, so pick up the 3.
those are the only two shared factors, so 2×3
now pick up whatever is not shared:
the two 2s for 8 and the 5 for 15 is not shared, add 2, 2, and 5 to the multiplication: 2×3×2×2×5=120
120 is the least common multiples of 6,8, and 15
this is basically how it is done. I believe you can explain better in your own words.
