A=x^2+4
(x^2+4)^2+32=12x^2+48
12x^2+48=12(x^2+4)
(x^2+4)^2+32=12(x^2+4)
a^2+32=12a
subtract 12a from both sides
a^2-12a+32=0
factor
(a-4)(a-8)=0
set each to zero
a-4=0
a=4
a-8=0
a=8
a=4 or 8
a=x^2+4
8=x^2+4 and
4=x^2+4
subtract 4
4=x^2
0=x^2
square root
+/-2=x
0=x
x=-2,0,2
ax^2+bx+c=0
coefficient of the a term is 1
constant=32
Answer:
a, Row 1 = 30 seats
Row 2 = 32 seats
Row 3 = 34 seats
Row 4 = 36 seats
b, n + equidistant number of seats added each row (2) * number of row - 1
c, 58 seats
Step-by-step explanation:
a, Because the seats is increasing by 2 after every row after row 1
Therefore, row 2 = row 1 + 2 = 30+2 = 32 seats
Row 3 = Row 2 + 2 =32+2 =34 seats
Row 4 = Row 3 + 2 = 34 + 2 = 36 seats
b, The explicit rule for the number of seats would be:
Row 1 = n
Row 2 = n + equidistant number of seats added each row (2) * (2-1) = n + 2
Row 3 = n+ equidistant number of seats added each row (2) * (3-1) = n+ 4
Row 4 = n + equidistant number of seats added each row(2) * (4-1) = n+6
etc.....
c, The number of seats in the 15th row would be = number of seat in the first row + equidistant number of seats added each row * 15 - 1 (first row)
= 30 + 2 * 14= 30 + 28 = 58 seats
Hope this help you :3
Answer:
Step-by-step explanation:
we know that
In this problem we have a exponential function of the form
where
y ----> represent the pool’s loss of water
x ----> the number of days
a is the initial value
a=25,700 gal
b ----> is the base
r=15%=15/100=0.15
b=(1-r)=1-0.15=0.85
The function is equal to
Assuming PQRS is a parallelogram, we have PQ = RS, and angles S and R are supplementary so their measures sum to 180°.
So
5<em>x</em> = <em>x</em> + 12
4<em>x</em> = 12
<em>x</em> = 3
→ PQ = 5<em>x</em> = 15
and
12<em>z </em>° + 6<em>z</em> ° = 180°
18<em>z</em> ° = 180°
<em>z</em> = 180/18 = 10
→ m∠<em>S</em> = 12•10° = 120°
Answer:
PS = 31.5 ft
Step-by-step explanation:
∠PTS = 180 - 16 = 154°
164°(π/180) = 41π/45 radians
PS = rθ = 11(41π/45) = 31.48573...
