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ra1l [238]
3 years ago
15

Match the expressions with the nonpermissible replacements for y

Mathematics
2 answers:
Tomtit [17]3 years ago
8 0

Answer:

-7     →     \dfrac{y^2-y+6}{-2(y+7)}

3/2  →      \dfrac{y^2-2y+1}{2y-3}

1      →      \dfrac{5y^2-6y+1}{-5(y-1)}

-1/4  →      \dfrac{y(y+5)}{4y+1}

Step-by-step explanation:

We need to find the nonpermissible replacements for y.

Equate the denominator of each expression equal to 0, to find the nonpermissible replacements for y.

First expression is

\dfrac{y^2-2y+1}{2y-3}

Equate (2y-3) equal to 0.

2y-3=0

Add 2 on both sides.

2y=3

Divide both sides by 3.

y=\dfrac{3}{2}

Therefore, 3/2 is the nonpermissible replacements for y.

Second expression is

\dfrac{y(y+5)}{4y+1}

Equate (4y+1) equal to 0.

4y+1=0

4y=-1

y=-\dfrac{1}{4}

Therefore, -1/4 is the nonpermissible replacements for y.

Third expression is

\dfrac{5y^2-6y+1}{-5(y-1)}

Equate -5(y-1) equal to 0.

-5(y-1)=0

y-1=0

y=1

Therefore, 1 is the nonpermissible replacements for y.

Fourth expression is

\dfrac{y^2-y+6}{-2(y+7)}

Equate -2(y+7) equal to 0.

-2(y+7)=0

y+7=0

y=-7

Therefore, -7 is the nonpermissible replacements for y.

pantera1 [17]3 years ago
3 0

<em>-7 _D_</em>

<em>\frac{3}{2} _A_</em>

<em>1 _C_</em>

<em>\frac{-1}{4} _B_</em>

<em>_A_ \frac{y^{2} -2y+1}{2y-3}</em>

<em>_B_ \frac{y(y+5)}{4y+1}</em>

<em>_C_ \frac{5y^{2}-6y+1 }{-5(y-1)}</em>

<em>_D_ \frac{y^{2}-y-6 }{-2(y+7)}</em>


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